PyQt的多线程例子

Question

机会是我太疲倦，需要睡觉，因为我已经做了线程前，但突然间我穿过其中规定一个常见的错误来的：

'global name 'self' is not defined'.

这里是码之前，我输入线程功能，

import thread 
import time 
import ystockquote 
import Tkinter as tk 
from threadexample import * 
import sys 
from PyQt4.QtGui import * 



class Window(QtGui.QDialog): 



    def __init__(self, parent=None): 
     QtGui.QWidget.__init__(self, parent) 
     self.ui = Ui_Dialog() 
     self.ui.setupUi(self) 


     style = QStyleFactory.create('Cleanlooks') 
     app.setStyle(style) 



if __name__ == "__main__": 

    app = QtGui.QApplication(sys.argv) 
    viewer = Window() 
    viewer.show() 

    sys.exit(app.exec_()) 

和在这里它与被称为（start_stream）穿线功能，

import thread 
import time 
import ystockquote 
import Tkinter as tk 
from threadexample import * 
import sys 
from PyQt4.QtGui import * 



class Window(QtGui.QDialog): 



    def __init__(self, parent=None): 
     QtGui.QWidget.__init__(self, parent) 
     self.ui = Ui_Dialog() 
     self.ui.setupUi(self) 


     style = QStyleFactory.create('Cleanlooks') 
     app.setStyle(style) 

     QtCore.QObject.connect(self.ui.startbutton, QtCore.SIGNAL('clicked()'),self.start_stream) 

    def start_stream(threadName, delay): 
     while True: 
      footsie = ystockquote.get_price('^FTSE') 
      self.ui.indexlabel.setText(footsie) 

    try: 
     thread.start_new_thread(start_stream, ("Now Streaming", 5,)) 
    except:    
     self.ui.indexlabel.setText("Error") 

    while True: 
     pass 


if __name__ == "__main__": 

    app = QtGui.QApplication(sys.argv) 
    viewer = Window() 
    viewer.show() 

    sys.exit(app.exec_()) 

Answer 1

的问题是在这里：

class Window(QtGui.QDialog): 
    ... 
    def start_stream(threadName, delay): 
     ... 

start_stream缺少self参数，所以当你尝试在方法中访问它，self将无法​​定义。