1
我试图用没有工作
货币创建一个对象中的JavaScript功能逻辑
期初余额
和期末余额
我有以下数据
var _ = require('underscore');
var accounts=[
{
"id":"20",
"name":"OASIS MALL-RMB Account",
"branchId":"6",
"type_id":"1",
"currency_id":"1",
"balance":"0",
"createdBy":"2",
"active":"1",
"ts":"2017-06-30 00:12:08"
},
{
"id":"21",
"name":"OASIS MALL-USD Account",
"branchId":"6",
"type_id":"1",
"currency_id":"2",
"balance":"0",
"createdBy":"2",
"active":"1",
"ts":"2017-06-30 00:12:09"
},
{
"id":"22","name":"OASIS MALL-DIRHAM Account",
"branchId":"6",
"type_id":"1",
"currency_id":"3",
"balance":"0",
"createdBy":"2",
"active":"1",
"ts":"2017-06-30 00:12:09"
},
{
"id":"23",
"name":"OASIS MALL-UGX Account",
"branchId":"6",
"type_id":"1",
"currency_id":"4",
"balance":"0",
"createdBy":"2",
"active":"1",
"ts":"2017-06-30 00:12:09"
},
{
"id":"24",
"name":"OASIS MALL-KSH Account",
"branchId":"6",
"type_id":"1",
"currency_id":"5",
"balance":"0",
"createdBy":"2",
"active":"1",
"ts":"2017-06-30 00:12:09"
}
]
var balances =[
{
"id":"101",
"branchId":"6",
"accountId":"20",
"openingBalance":"3260000",
"closingBalance":"3260000",
"date":"2017-08-15",
"ts":"2017-08-15 02:27:08"
},
{
"id":"102",
"branchId":"6",
"accountId":"21",
"openingBalance":"1882492",
"closingBalance":"1882492",
"date":"2017-08-15",
"ts":"2017-08-15 02:27:08"
},
{
"id":"103","branchId":"6",
"accountId":"22",
"openingBalance":"-3000",
"closingBalance":"-3000",
"date":"2017-08-15",
"ts":"2017-08-15 02:27:08"
},
{
"id":"104",
"branchId":"6",
"accountId":"23",
"openingBalance":"95199318",
"closingBalance":"95199318",
"date":"2017-08-15",
"ts":"2017-08-15 02:27:08"
},
{
"id":"105",
"branchId":"6",
"accountId":"24",
"openingBalance":"1847000",
"closingBalance":"1847000",
"date":"2017-08-15",
"ts":"2017-08-15 02:27:08"
}
]
我知道如何在循环和if语句中做到这一点。但我想这样做的功能方式 我已经尝试编写此代码。
var DisplayAccounts = function(accounts,balances){
var displayaccounts = _(accounts).map((x)=>{
var mybalance = _(balances)
.reduce((acc,z)=>{
acc={
currency :x.currency_id,
openingBalance : z.openingBalance,
closingBalance : z.closingBalance
};
return acc;
},{});
return mybalance;
});
return displayaccounts;
}
console.log(DisplayAccounts(accounts,balances));
但它给了我一个我不喜欢的答案。 IT给我
[ { currency: '1',
openingBalance: '1847000',
closingBalance: '1847000' },
{ currency: '2',
openingBalance: '1847000',
closingBalance: '1847000' },
{ currency: '3',
openingBalance: '1847000',
closingBalance: '1847000' },
{ currency: '4',
openingBalance: '1847000',
closingBalance: '1847000' },
{ currency: '5',
openingBalance: '1847000',
closingBalance: '1847000' } ]
相同的期初和期末余额通过。我需要每种货币都与其相应的期初和期末余额一样。
[ { currency: '1',
openingBalance: '3260000',
closingBalance: '3260000' },
{ currency: '2',
openingBalance: '1882492',
closingBalance: '1882492' },
{ currency: '3',
openingBalance: '-3000',
closingBalance: '-3000' },
{ currency: '4',
openingBalance: '95199318',
closingBalance: '95199318' },
{ currency: '5',
openingBalance: '1847000',
closingBalance: '1847000' } ]
它怎么做到的?
谢谢。如果有人给了我一个纯粹功能性的答案,我会评价它并接受它 – henrybbosa
但等待@DevDig这对我来说似乎是一个纯粹的功能。你能告诉我为什么它不纯吗? – henrybbosa
@HenryBbosa由于函数式编程是一个范例,有些人可能认为这是功能性的。然而,一些纯粹主义者可能会将函数式编程定义为“构成纯函数”,因此帐号映射函数中不会有'状态'(b变量)。 – DevDig