SQL - 返回累计每月列值

Question

我有这个SQL查询，我用它来查找每月每个帐户的试算平衡移动。

/* Fixed Assets 1 */ 
SELECT * FROM 
(
    SELECT T0.AcctCode AS 'SAP Code', T0.AcctName AS 'Description', 
    MONTH(T1.RefDate) AS Month, SUM(T1.Debit - T1.Credit) AS 'Amount' 
    FROM OACT T0 
    LEFT JOIN JDT1 T1 ON T0.[AcctCode] = T1.[Account] 
    WHERE T0.AcctCode LIKE '111%' AND T0.Levels = 5 
    AND (T1.RefDate BETWEEN DATEADD(yy, DATEDIFF(yy,0,{?AsAtDate}), 0) AND {?AsAtDate}) 
    GROUP BY T0.AcctCode, T0.AcctName, T0.FatherNum, T1.RefDate) AS q 
    PIVOT 
(
SUM(Amount) 
FOR [Month] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12]) 
) AS query 

这从六月返回以下结果：

我想包括这样的所有行按月累积结果该行 1次的结果应该是：

1, 111110, Building Gross Value, 633604.23, 637764.23, 645313.03, 649061.78, 651097.78, 651097.78, 651397.78 

我没有成功实现这一目标。如何修改查询来实现此目的？

其他数据：

查询：

SELECT CAST(T0.TaxDate AS Date), T0.Account, T1.AcctName, T0.Debit, T0.Credit 
FROM JDT1 T0 INNER JOIN OACT T1 
ON T0.Account = T1.AcctCode 
WHERE T0.[Account] = '111110' 

返回：

Answer 1

需要外选择在其中添加列转移到另一个：

SELECT AcctCode AS 'SAP Code', AcctName AS 'Description', 
col1 AS '1', 
col1 + col2 AS '2', 
col1 + col2 + col3 AS '3', 
... FROM (
    SELECT AcctCode, AcctName, 
    [1] AS col1, 
    [2] AS col2, 
    [3] AS col3, 
    ... FROM 
    (
     SELECT T0.AcctCode, T0.AcctName, 
     MONTH(T1.RefDate) AS Month, SUM(T1.Debit - T1.Credit) AS 'Amount' 
     FROM OACT T0 
     LEFT JOIN JDT1 T1 ON T0.[AcctCode] = T1.[Account] 
     WHERE T0.AcctCode LIKE '111%' AND T0.Levels = 5 
     AND (T1.RefDate BETWEEN DATEADD(yy, DATEDIFF(yy,0,{?AsAtDate}), 0) AND {?AsAtDate}) 
     GROUP BY T0.AcctCode, T0.AcctName, T0.FatherNum, T1.RefDate) AS q 
     PIVOT 
    (
    SUM(Amount) 
    FOR [Month] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12]) 
    ) AS query 
) 

Answer 2

最直接的方法是转储枢轴的结果到一个临时表，或如果数据集相当小，则为表变量。然后，只需使用UNION从PIVOT获取累积结果和子类别。这是一个使用表变量的例子。

/* Fixed Assets 1 */ 
SELECT * 
INTO #FixedAssets FROM 
(
    SELECT T0.AcctCode AS 'SAP Code', T0.AcctName AS 'Description', 
    MONTH(T1.RefDate) AS Month, SUM(T1.Debit - T1.Credit) AS 'Amount' 
    FROM OACT T0 
    LEFT JOIN JDT1 T1 ON T0.[AcctCode] = T1.[Account] 
    WHERE T0.AcctCode LIKE '111%' AND T0.Levels = 5 
    AND (T1.RefDate BETWEEN DATEADD(yy, DATEDIFF(yy,0,{?AsAtDate}), 0) AND {?AsAtDate}) 
    GROUP BY T0.AcctCode, T0.AcctName, T0.FatherNum, T1.RefDate) AS q 
    PIVOT 
(
SUM(Amount) 
FOR [Month] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12]) 
) AS query 
GO 

SELECT 
     [SAP Code] = '111110' 
    , [Description] = 'Building Gross Value' 
    , [1]   = SUM([1]) 
    , [2]   = SUM([2]) 
    , [3]   = SUM([3]) 
    , [4]   = SUM([4]) 
    , [5]   = SUM([5]) 
    , [6]   = SUM([6]) 
    , [7]   = SUM([7]) 
    , [8]   = SUM([8]) 
    , [9]   = SUM([9]) 
    , [10]   = SUM([10]) 
    , [11]   = SUM([11]) 
    , [12]   = SUM([12]) 
UNION 
SELECT * FROM #FixedAssets 
ORDER BY 1 

Answer 3

如果我明白你的问题正确，则需要按月累积结果在一排用逗号分隔的借记值

create table a 
(dateval date, acc int,accname varchar(100), debit decimal(10,2)) 

insert into a 
values 
('20150630', 111110, 'Building Gross Value', 633604.230), 
('20150731', 111110, 'Building Gross Value', 2760.000000), 
('20150730', 111110, 'Building Gross Value', 1400.000000), 
('20150808', 111110, 'BUIIdlngGrossValue', 1890.00), 
('20150811', 111110, 'BUIIdlnanossValue', 180.00), 
('20150811', 111110, 'Building Gross Value', 375.000000), 
('20150819', 111110, 'Building Gross Value', 2622.200000), 
('20150821', 111110, 'Building Gross Value', 360.000000), 
('20150822', 111110, 'Building Gross Value', 21.600000), 
('20150824', 111110, 'Building Gross Value', 100.000000), 
('20150825', 111110, 'Building Gross Value', 770.000000), 
('20150829', 111110, 'Building Gross Value', 100.000000), 
('20150831', 111110, 'Building Gross Value', 340.000000), 
('20150831', 111110, 'Building Gross Value', 790.000000), 
('20150924', 111110, 'Building Gross Value' ,918.750000), 
('20150928', 111110, 'Building Gross Value', 2830.000000), 
('20151005', 111110, 'Building Gross Value', 1411.000000), 
('20151023', 111110, 'Building Gross Value', 625.000000) 

现在下面提到的查询会以逗号分隔值给出一行结果。

with cte as 
(
select * from 
(
    select a.dateval,b.acc,b.accname,sum(b.debit) as debit,row_number() over (partition by year(a.dateval),month(a.dateval) order by a.dateval desc) as rn 
    from (select distinct dateval from a) as a 
    inner join a as b 
    on a.dateval >= b.dateval 
    group by a.dateval,b.acc,b.accname 
) as a 
where rn = 1 
) 
select acc,accname,stuff((select ',' + cast(debit as varchar(1000)) from cte as b where a.acc = b.acc for xml path ('')),1,1,'') 
from cte as a 
group by acc,accname