通过AJAX传输变量

Question

我目前正在处理日历。在日历旁边，我想要一个描述框，其中当用户单击日历中的日期时，应该显示有关该事件的更多信息。

我直到现在： HTML/PHP：

// Variables from MySQL request:  
$event 
$date 
$place 
$start 
$end 

<button type="button" onclick="event_description()">$day</button> 

<div id="details"></div> 

AJAX：

function event_description() { 
    var xhttp = new XMLHttpRequest(); 
    xhttp.onreadystatechange = function() { 
    if (xhttp.readyState == 4 && xhttp.status == 200) { 
     document.getElementById("details").innerHTML = xhttp.responseText; 
    } 
    }; 
    xhttp.open("GET", "kalender/description.php", true); 
    xhttp.send(); 
} 

所以我能做些什么，所以我可以使用MySQL变量在description.php？

感谢您的帮助！

Answer 1

您可以使用这样的事情..

// Variables from MySQL request:   
$event 
$date 
$place 

///pass all the parameters in onclick function as arguments 

<button type="button" onclick="event_description('<?php echo $event ?>','<?php echo $date ?>','<?php echo $place ?>')">$day</button> 
<div id="details"></div> 

Script代码

<script> 
///get all the params here in function 
function event_description(event_name,date,place) { 
    var xhttp = new XMLHttpRequest(); 
    xhttp.onreadystatechange = function() { 
    if (xhttp.readyState == 4 && xhttp.status == 200) { 
     document.getElementById("details").innerHTML = xhttp.responseText; 
    } 
    }; 

    /////create a string of all the parameters and pass this with requested url as query string and get all these params in target file using `$_GET[]` 

    var params = 'event_name='+event_name+'&date='+date+'&place='+place; 
    xhttp.open("GET", "kalender/description.php?"+params, true); 
    xhttp.send(); 
} 
</script>