这bash脚本是给我的错误，我想不通为什么

Question

我在这里以下一些教程，每当我执行，我得到

Do you want to create a bukkit server on this computer? (Hint: answer YES or NO) > no 
answered no 
./test.sh: line 44: syntax error near unexpected token `else' 
./test.sh: line 44: 'else' 

这里的脚本：

while true; do 
    read -p "Do you want to create a bukkit server on this computer? (Hint: answer YES or NO) > " yn 
    case $yn in 
     [Yy]*) echo answered yes; INSTALL="Y"; break;; 
     [Nn]*) echo answered no; break;; 
     *) echo "Please answer yes or no.";; 
    esac 
done 

if [ -z "$INSTALL" ]; 
    echo "Yay!" 
else 
    echo "Sadface!" 
fi 

我是一个新手的bash：/

Answer 1

你错过了病情后then关键字：

if [ -z "$INSTALL" ]; then 
    echo "Yay!" 
else 
    echo "Sadface!" 
fi 

Answer 2

你需要一个then后if：

while true; do 
read -p "Do you want to create a bukkit server on this computer? (Hint: answer YES or NO) > " yn 
case $yn in 
[Yy]*) echo answered yes; INSTALL="Y"; break;; 
[Nn]*) echo answered no; break;; 
*) echo "Please answer yes or no.";; 
esac 
done 

if [ -z "$INSTALL" ]; then 
echo "Yay!" 
else 
echo "Sadface!" 
fi