我想在我的CakePHP程序纳入上传功能。我之前为一个原始的PHP项目创建了一个,并决定重用该代码,因为我知道它的工作原理。代码如下:无法上传文件中的CakePHP 2
$allowed_filetypes = array('.jpg','.gif','.bmp','.png');
$max_filesize = 1000000; // Maximum filesize in BYTES
$upload_path = './files/';
$filename = $_FILES['userfile']['name'];
$desiredname = $_POST['desiredname'];
$ext = substr($filename, strpos($filename,'.'), strlen($filename)-1);
$savedfile = $desiredname.$ext;
// Check if the filetype is allowed, if not DIE and inform the user.
if(!in_array($ext,$allowed_filetypes))
die('The file you attempted to upload is not allowed.');
// Now check the filesize, if it is too large then DIE and inform the user.
if(filesize($_FILES['userfile']['tmp_name']) > $max_filesize)
die('The file you attempted to upload is too large.');
// Check if we can upload to the specified path, if not DIE and inform the user.
if(!is_writable($upload_path))
die('You cannot upload to the specified directory, please CHMOD it to 777.');
// Upload the file to your specified path.
if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $savedfile))
echo 'Your file upload was successful, view the file <a href="' . $upload_path . $savedfile . '" title="Your File">here</a>'; // It worked.
else
echo 'There was an error during the file upload. Please try again.'; // It failed :(.
我把这段代码放到我想上传的页面的控制器中。我已经使用了表单助手在CakePHP中产生的形式,主要内容如下:
<?php
echo $this->Form->create('Customer', array(
'class' => 'form-horizontal',
'action' => 'add',
'enctype' => 'multipart/form-data'
));
echo $this->Form->input('filename', array(
'type' => 'text',
'label' => 'Filename',
'class' => 'span5'
));
echo $this->Form->input('file', array(
'between' => '<br />',
'type' => 'file'
));
echo $this->Form->end('Save Changes', array(
'label' => false,
'type' => 'submit',
'class' => 'btn btn-primary'
));
echo $this->Form->end();
?>
我已经改变到田间地头的任何引用在我的旧代码,以反映该项目中使用形式的变化。然而,我得到以下错误,当我提交表单:
通知(8):未定义指数:CustomerFile [APP \控制器\ CustomersController.php,线148]
通知(8):未定义的索引:CustomerFilename [APP \控制器\ CustomersController.php,线149]
在控制器中的代码,我已(再次)改变表单字段使用以下:
$filename = $this->request->data['CustomerFile']['name'];
$desiredname = $this->request->data['CustomerFilename'];
但仍然出现了错误。我猜测,表单字段没有被引用正确的,但我想我已经正确引用他们使用$this->request
代码,但显然没有奏效。有没有人有任何想法?