2013-04-17 71 views
0

这里是我的查询,我现在用的Hiberante运行:SQL查询休眠不工作:ORA-00923:FROM关键字未找到预期

String sqlStr = "SELECT {User.*}," + 
          "{Address.*} from T_USER_DETAILS2 US,T_ADDRESS_DETAILS AD where US.ADDRESS_ID = AD.ADDRESS_ID" + 
          " AND US.USER_FIRSTNAME = :firstname"; 

    SQLQuery sql = session.createSQLQuery(sqlStr).addEntity("User",User.class).addEntity("Address",Address.class); 
    sql.setParameter("firstname", firstname); 

    System.out.println("Query created, now executing the query in the database"); 

    List<Object[]> list = sql.list(); 

这里是由Hibernate生成的查询:

Hibernate: 
    /* dynamic native SQL query */ SELECT 
     User.USER_ID as USER1_1_0_, 
     User.ADDRESS_ID as ADDRESS9_1_0_, 
     User.USER_AGE as USER2_1_0_, 
     User.USER_EMAIL as USER3_1_0_, 
     User.USER_FIRSTNAME as USER4_1_0_, 
     User.USER_LASTNAME as USER5_1_0_, 
     User.USER_PASSWORD as USER6_1_0_, 
     User.USER_COUNTRY_CODE as USER7_1_0_, 
     User.USER_PHONE as USER8_1_0_, 
     Address.ADDRESS_ID as ADDRESS1_0_1_, 
     Address.ADDRESS_LINE1 as ADDRESS2_0_1_, 
     Address.ADDRESS_LINE2 as ADDRESS3_0_1_, 
     Address.CITY as CITY0_1_, 
     Address.COUNTRY as COUNTRY0_1_, 
     Address.STATE as STATE0_1_ 
    from 
     T_USER_DETAILS2 US, 
     T_ADDRESS_DETAILS AD 
    where 
     US.ADDRESS_ID = AD.ADDRESS_ID 
     AND US.USER_FIRSTNAME = ? 

我收到此错误:

捉住:org.hibernate.exception.SQLGrammarException:ORA-00923:FROM关键字未找到预期

我知道这个错误是因为我们错过了select子句中的一些逗号。但我可以看到选择中的一切都很完美。任何人都可以帮助我解决这个问题。

+0

'用户'是一个保留字,需要引用:''User“.USER_ID'而不是'User.USER_ID'。但是在查询中没有名为'User'的表别名。别名是“US”。你应该使用明确的'JOIN's而不是隐式的。 –

+0

不,这是不是问题,据我所知...和有关该别名...我用别名US加入表..因为两个表包含具有相同名称的列,所以这可能会造成歧义在休眠结束(映射)。这是我们如何在hibernate中获取多个实体。检查我的.addEnity(“用户”,User.class)别名是从那里来的 – shashi

回答

3

当我从数据源bean中删除<property name="validationQuery" value="SELECT 1"/>时,它对我有效。您也可以将其更改为SELECT 1 from DUAL

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