2017-01-10 139 views
2

我需要从各种元素的长列表中提取所有属性。因此,我正在试图构建一个循环,遍历所有元素并返回它们的属性。提取元素属性的循环XML

通过几个帖子,我已经能够写下面的代码。然而,我有超过1000个元素,为什么我会非常高兴,如果它有可能围绕后者建立一个循环而不是复制所有元素。

with cte as 
(
select cast(
'<schema fwRel="2"> 
<taxFormId isPrimeKey="true" fkRef="C1-TXFRM" mapField="TAX_FORM_ID" dataType="string"/> 
<formType fkRef="C1-FRMTY" mapField="FORM_TYPE_CD" dataType="string"/> 
<bo suppress="true" required="true" fkRef="F1-BUSOB" mapField="BUS_OBJ_CD" dataType="string"/> 
<transferReason mdField="C1_TXF_TFRRSN_FLG" dataType="lookup" mapXML="BO_DATA_AREA" lookup="C1_TXF_TFRRSN_FLG"/> 
</schema>' as xml) xml_col 
) 

select cte.xml_col.value('(/schema/taxFormId/@fkRef)[1]', 'varchar(100)') as Dummy1 
cte.xml_col.value('(/schema/taxFormId/@mapField)[1]', 'varchar(100)') as Dummy2 
cte.xml_col.value('(/schema/taxFormId/@dataType)[1]', 'varchar(100)') as Dummy3 
cte.xml_col.value('(/schema/taxFormId/@mapXML)[1]', 'varchar(100)') as Dummy4 

from cte 

我希望我已经提供了足够的信息

+0

您提到的代码 - 你可以添加它吗? – Damian

+0

不知怎么,边缘把我搞砸了。现已附上 –

回答

1

一个简单的方法来获取属性上市:

with cte as 
(
select cast(
'<schema fwRel="2"> 
    <taxFormId isPrimeKey="true" fkRef="C1-TXFRM" mapField="TAX_FORM_ID" dataType="string" /> 
    <formType fkRef="C1-FRMTY" mapField="FORM_TYPE_CD" dataType="string" /> 
    <bo suppress="true" required="true" fkRef="F1-BUSOB" mapField="BUS_OBJ_CD" dataType="string" /> 
    <transferReason mdField="C1_TXF_TFRRSN_FLG" dataType="lookup" mapXML="BO_DATA_AREA" lookup="C1_TXF_TFRRSN_FLG" /> 
</schema>' as xml) xml_col 
) 

- 查询使用.nodes(N'/schema/*')列出以下<schema>.nodes(N'@*')所有节点列出所有属性此节点中:

select nd.value(N'local-name(.)',N'nvarchar(max)') AS NodeName 
     ,attr.value(N'local-name(.)',N'nvarchar(max)') AS AttrName 
     ,attr.value(N'.',N'nvarchar(max)') AS AttrValue 
from cte 
OUTER APPLY xml_col.nodes(N'/schema/*') AS A(nd) 
OUTER APPLY A.nd.nodes(N'@*') AS B(attr) 

结果:

taxFormId  isPrimeKey true 
taxFormId  fkRef  C1-TXFRM 
taxFormId  mapField TAX_FORM_ID 
taxFormId  dataType string 
formType  fkRef  C1-FRMTY 
formType  mapField FORM_TYPE_CD 
formType  dataType string 
bo    suppress true 
bo    required true 
bo    fkRef  F1-BUSOB 
bo    mapField BUS_OBJ_CD 
bo    dataType string 
transferReason mdField  C1_TXF_TFRRSN_FLG 
transferReason dataType lookup 
transferReason mapXML  BO_DATA_AREA 
transferReason lookup  C1_TXF_TFRRSN_FLG 

如果你需要像在您的示例声明一个可以动态创建(作为字符串)并使用EXEC来执行此操作(动态SQL)。

+0

谢谢!这节省了我的一天:) –

0

这可能是有点过杀人,但我经常使用TVF来解析和散列大型XML文件。该函数将返回具有范围键R1/R2的父/子层次结构中的数据。

例如:

Declare @XML xml=' 
<schema fwRel="2"> 
    <taxFormId isPrimeKey="true" fkRef="C1-TXFRM" mapField="TAX_FORM_ID" dataType="string"/> 
    <formType fkRef="C1-FRMTY" mapField="FORM_TYPE_CD" dataType="string"/> 
    <bo suppress="true" required="true" fkRef="F1-BUSOB" mapField="BUS_OBJ_CD" dataType="string"/> 
    <transferReason mdField="C1_TXF_TFRRSN_FLG" dataType="lookup" mapXML="BO_DATA_AREA" lookup="C1_TXF_TFRRSN_FLG"/> 
</schema>' 

Select * from [dbo].[udf-XML-Hier](@XML) Order by R1 

返回

enter image description here

你会注意到,对于元素名称栏,属性名,XPath的,标题(可选),和价值。 R1,R2,Lv1,ID和PT都是派生的。

作为一个TVF,你可以应用任何WHEREORDER所需


的UDF(与原始来源)如果有兴趣

CREATE FUNCTION [dbo].[udf-XML-Hier](@XML xml) 

Returns Table 
As Return 

with cte0 as ( 
        Select Lvl  = 1 
         ,ID  = Cast(1 as int) 
         ,Pt  = Cast(NULL as int) 
         ,Element = x.value('local-name(.)','varchar(150)') 
         ,Attribute = cast('' as varchar(150)) 
         ,Value  = x.value('text()[1]','varchar(max)') 
         ,XPath  = cast(concat(x.value('local-name(.)','varchar(max)'),'[' ,cast(Row_Number() Over(Order By (Select 1)) as int),']') as varchar(max)) 
         ,Seq  = cast(10000001 as varchar(max)) 
         ,AttData = x.query('.') 
         ,XMLData = x.query('*') 
        From @XML.nodes('/*') a(x) 
        Union All 
        Select Lvl  = p.Lvl + 1 
         ,ID  = Cast((Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int) * 10 
         ,Pt  = p.ID 
         ,Element = c.value('local-name(.)','varchar(150)') 
         ,Attribute = cast('' as varchar(150)) 
         ,Value  = cast(c.value('text()[1]','varchar(max)') as varchar(max)) 
         ,XPath  = cast(concat(p.XPath,'/',c.value('local-name(.)','varchar(max)'),'[',cast(Row_Number() Over(PARTITION BY c.value('local-name(.)','varchar(max)') Order By (Select 1)) as int),']') as varchar(max)) 
         ,Seq  = cast(concat(p.Seq,' ',10000000+Cast((Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int) * 10) as varchar(max)) 
         ,AttData = c.query('.') 
         ,XMLData = c.query('*') 
        From cte0 p 
        Cross Apply p.XMLData.nodes('*') b(c) 
      ) 
    , cte1 as ( 
        Select R1 = Row_Number() over (Order By Seq),A.* 
        From (
          Select Lvl,ID,Pt,Element,Attribute,Value,XPath,Seq From cte0 
          Union All 
          Select Lvl  = p.Lvl+1 
           ,ID  = p.ID + Row_Number() over (Order By (Select NULL)) 
           ,Pt  = p.ID 
           ,Element = p.Element 
           ,Attribute = x.value('local-name(.)','varchar(150)') 
           ,Value  = x.value('.','varchar(max)') 
           ,XPath  = p.XPath + '/@' + x.value('local-name(.)','varchar(max)') 
           ,Seq  = cast(concat(p.Seq,' ',10000000+p.ID + Row_Number() over (Order By (Select NULL))) as varchar(max)) 
          From cte0 p 
          Cross Apply AttData.nodes('/*/@*') a(x) 
         ) A 
       ) 

Select A.R1 
     ,R2 = IsNull((Select max(R1) From cte1 Where Seq Like A.Seq+'%'),A.R1) 
     ,A.Lvl 
     ,A.ID 
     ,A.Pt 
     ,A.Element 
     ,A.Attribute 
     ,A.XPath 
     ,Title = Replicate('|---',Lvl-1)+Element+IIF(Attribute='','','@'+Attribute) 
     ,A.Value 
From cte1 A 

/* 
Source: http://beyondrelational.com/modules/2/blogs/28/posts/10495/xquery-lab-58-select-from-xml.aspx 

Declare @XML xml='<person><firstname preferred="Annie" nickname="BeBe">Annabelle</firstname><lastname>Smith</lastname></person>' 
Select * from [dbo].[udf-XML-Hier](@XML) Order by R1 
*/ 
+0

谢谢! :)我设法得到这个工作以及。但是,正如你自己所说,这只是一个小小的矫枉过正。 –