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嗨我有这个代码从python列表中选择项目。问题是,一旦它遍历虽然循环工作不正常
CODE:
import re
name = input
while True:
name = input("Please enter your search term here:").lower()
def FindName(name,list1):
""" searches for a pattern in the list, returns the complete list entry. Is case sensitive.
May return incomplete value if ' is in the list value (ie confucius's)"""
if name in list1:
return name
else:
string1 = str(list1).replace('"',"'")
pattern = re.compile("[']"+name+"[^']*")
match = re.search(pattern,string1)
if match:
if match.group().lstrip("'") in list1:
return match.group().lstrip("'")
else:
print 'Fail %s' %match.group().lstrip("'")
return None
else:
return ' '.join(name2)
china=['In', 'China', 'people', 'teach',"Confusius's",
'teachings','dilligently.','Those',"Confusius''s",
'teachings','are','called','Taoism.']
india=['India', 'bopal', 'mahindra', 'gujarat',"gandhi's",
'bombay',"Gandhi",] ]
name2 = name[:]
this= ' '.join(name2)
print FindName(this,china)
for item in china:
print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]
this = ' '.join(name2)
for item in india:
print [(i,x) for (i,x) in enumerate(india) if x.startswith(this)]
this = ' '.join(name2)
for item in india:
print [(i,x) for (i,x) in enumerate(india) if x.endswith(this)]
this = ' '.join(name2)
for item in india:
print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]
loop continues......
的问题是,我试图把环路上的突破,但它仍然打印:print [(i,x) for (i,x) in enumerate...
在每个循环,因为它下降的循环。我怎样才能让它遍历报表,但只打印没有循环和打印print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]
等目标项目?
嘿所有,感谢您的输入。这很值得! – wakamdr