排序字典对象数组

Question

即时通讯的问题是，我不能排序NSMutableDictionary对象的NSMutableArray，我想通过评级排序对象，评级是一个NSNumber，我失踪了什么？

我当前的代码，总结所有的评级从“arrayMealRating”和排序结果数组：

  [arrayMealRating addObject:[NSMutableDictionary dictionaryWithObjectsAndKeys: 
             [eachObject objectForKey:@"Airline"], @"Airline" 
             ,[eachObject objectForKey:@"setMealRating"], @"setMealRating" 
             , nil]]; 

     } 
     NSArray *airlineNames = [arrayMealRating valueForKeyPath:@"@distinctUnionOfObjects.Airline"]; 

     // Loop through all the airlines 
     for (NSString *airline in airlineNames) { 

      // Get an array of all the dictionaries for the current airline 
      NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(Airline == %@)", airline]; 
      NSArray *airlineMealRating = [arrayMealRating filteredArrayUsingPredicate:predicate]; 

      // Get the sum of all the ratings using KVC @sum collection operator 
      NSNumber *rating = [airlineMealRating valueForKeyPath:@"@sum.setMealRating"]; 

      //NSLog(@"%@: %@", airline, rating); 
      [sortedMealArray addObject:[NSMutableDictionary dictionaryWithObjectsAndKeys: 
             airline, @"Airline" 
             ,[rating stringValue], @"setMealRating" 
             , nil]]; 
     } 



     NSSortDescriptor *descriptor = [[NSSortDescriptor alloc] initWithKey:@"setMealRating" ascending:YES]; 
     [sortedMealArray sortedArrayUsingDescriptors:[NSMutableArray arrayWithObjects:descriptor,nil]]; 
     auxMealRating = [sortedMealArray copy]; 

有任何疑问，请不要向下票，就问我，我会编辑的问题。

最好的问候和抱歉，我可怜的英语。

Answer 1

这应该做你想要什么：

NSArray *sortedArray = [arrayMealRating sortedArrayUsingComparator:^(id obj1, id obj2) { 
    NSNumber *rating1 = [(NSDictionary *)obj1 objectForKey:@"setMealRating"]; 
    NSNumber *rating2 = [(NSDictionary *)obj2 objectForKey:@"setMealRating"]; 
    return [rating1 compare:rating2]; 
}];