2012-05-29 164 views
3

我已经搜索了这个,但徒劳无功。 问题是我有两个列表,先用元件例如R:基于另一个列表重复列表的元素

my.list<-list(c('a','b','c','d'), c('g','h')) 

和第二列表被重复 是每个元素将被重复

repeat.list<-list(c(5,7,6,1), c(2,3)) 

我的次数像以形成其中在每个my.list元件是基于在repeat.list 即 结果重复一个新的列表:

[[1]] 
[1] "a" "a" "a" "a" "a" "b" "b" "b" "b" "b" "b" "b" "c" "c" "c" "c" "c" "c" "d" 
[[2]] 
[1] "g" "g" "h" "h" "h" 

预先感谢您的帮助

回答

6

使用mapply

mapply(rep, my.list, repeat.list) 
[[1]] 
[1] "a" "a" "a" "a" "a" "b" "b" "b" "b" "b" "b" "b" "c" "c" "c" "c" "c" "c" "d" 

[[2]] 
[1] "g" "g" "h" "h" "h" 

lapply也做的伎俩,但更详细:

lapply(seq_along(my.list), function(i)rep(my.list[[i]], repeat.list[[i]])) 
[[1]] 
[1] "a" "a" "a" "a" "a" "b" "b" "b" "b" "b" "b" "b" "c" "c" "c" "c" "c" "c" "d" 

[[2]] 
[1] "g" "g" "h" "h" "h" 
+0

共同负担:P –

相关问题