3
我做了一个简单的游戏(当然不是真正的游戏),玩家可以在4x20个字符的房间中移动。它在控制台中运行。如何在不按下每次输入的情况下获得输入?
但是在我的游戏循环中,我希望能够在房间内四处移动,而不必每次输入时都要输入。玩家应该可以按w/a/s/d并立即更新屏幕,但我不知道该怎么做。
public class Main{
public static void main(String[] args){
MovementLoop();
}
public static void MovementLoop(){
Scanner input = new Scanner(System.in);
int pos=10, linepos=2;
String keypressed;
boolean playing = true;
while(playing == true){
display dObj = new display(linepos, pos);
dObj.drawImage();
keypressed=input.nextLine();
if(keypressed.equals("w")){
linepos -= 1;
}
else if(keypressed.equals("s")){
linepos += 1;
}
else if(keypressed.equals("a")){
pos -= 1;
}
else if(keypressed.equals("d")){
pos += 1;
}
else if(keypressed.equals("q")){
System.out.println("You have quit the game.");
playing = false;
}
else{
System.out.println("\nplease use w a s d\n");
}
}
}
}
public class display{
private String lines[][] = new String[4][20];
private String hWalls = "+--------------------+";
private String vWalls = "|";
private int linepos, pos;
public display(int linepos1, int pos1){
pos = pos1 - 1;
linepos = linepos1 - 1;
}
public void drawImage(){
for(int x1=0;x1<lines.length;x1++){
for(int x2=0;x2<lines[x1].length;x2++){
lines[x1][x2]="#";
}
}
lines[linepos][pos]="O";
System.out.println(hWalls);
for(int x2=0;x2<lines.length;x2++){
System.out.print(vWalls);
for(int x3=0;x3<lines[x2].length;x3++){
System.out.print(lines[x2][x3]);
}
System.out.println(vWalls);
}
System.out.println(hWalls);
}
}
布尔禅!不要使用'while(foo == true)',只需使用'while(foo)'。避免使用== == true和== == false是很好的风格。 – fvrghl
可能的重复[如何从Java控制台读取单个字符(用户键入它)?](http://stackoverflow.com/questions/1066318/how-to-read-a-single-char-从 - 控制台在Java中作为用户类型,它) –
检查此 - http://stackoverflow.com/questions/1864076/equivalent-function-to-cs-getch-in-java –