2015-04-28 52 views
-1

我需要一个查询,它将赋予与某些值相对应的行是强制性的,无论其值是否为空值或这些值在表中都不存在。MySQL:查询获得一些强制行

E.g.

SELECT spot_key, market,panel_member, SUM(weight) as TVR 
FROM break_minute_tvr_fixed b 
WHERE b.column1 in (1,3,4,2,3,4) 
    and b.section in (1,2,3,4) 
    and b.sex in (1,2) 
    and b.age in (1,2,3,4,5,6,7) 
    and b.market in ('9') 
    and spot_key in ('1:20141017:2129') 
GROUP BY spot_key, market; 

这将返回行为:

+-----------------+--------+---------------------+--------------------+ 
| spot_key  | market | panel_member  | TVR    | 
+-----------------+--------+---------------------+--------------------+ 
| 1:20141017:2129 | 9  | 010583010102;7.2930 | 134.65280079841614 | 
+-----------------+--------+---------------------+--------------------+ 
1 row in set (0.00 sec) 

现在,如果我添加其他价值的市场名单好比说300不那么本身我的查询变得表存在:

SELECT spot_key, market,panel_member, SUM(weight) as TVR 
    FROM break_minute_tvr_fixed b 
WHERE b.column1 in (1,3,4,2,3,4) 
    and b.section in (1,2,3,4) 
    and b.sex in (1,2) 
    and b.age in (1,2,3,4,5,6,7) 
    and b.market in ('9','300') 
    and spot_key in ('1:20141017:2129') 
GROUP BY spot_key, market; 

它给了我与上面相同的输出。但我需要的东西象下面这样:

+-----------------+--------+---------------------+--------------------+ 
| spot_key  | market | panel_member  | TVR    | 
+-----------------+--------+---------------------+--------------------+ 
| 1:20141017:2129 | 300 |      | 0     | 
| 1:20141017:2129 | 9  | 010583010102;7.2930 | 134.65280079841614 | 
+-----------------+--------+---------------------+--------------------+ 
+0

删除“GROUP BY”子句后你尝试过吗? –

+0

因此在'break_minute_tvr_fixed'中没有'market' ='300'的行,但是您想要在结果中显示它们以及'spot_key'吗?旁边的问题:你为什么只用1个'spot_key'?你能有超过1个spot_key吗?如果是的话,希望的输出是什么?所有的“spot_key”和“market”配对? – Doon

+0

是@Doon你是对的。在“in”子句中我们可以有多个spot_key。 在这种情况下,我需要所有的组合。 –

回答

2

您可以用left join做到这一点:

SELECT spot_key, m.market, panel_member, SUM(weight) as TVR 
FROM (SELECT '9' as market UNION ALL SELECT '300' 
    ) LEFT JOIN 
    break_minute_tvr_fixed b 
    ON b.market = m.market and 
     b.column1 in (1,3,4,2,3,4) and 
     b.section in (1,2,3,4) and 
     b.sex in (1,2) and 
     b.age in (1,2,3,4,5,6,7) and 
     b.spot_key in ('1:20141017:2129') 
GROUP BY spot_key, market; 

当然spot_key中会NULL,除非你明确地给它分配一个值:

SELECT '1:20141017:2129' as spot_key, m.market, panel_member, SUM(weight) as TVR