C＃对象面板

Question

我遇到的问题是我可以成功使用我创建的Room对象的RoomID，但不能使用面板。这里是我将标签设置为房间名称的功能。 （这是我的Form1.cs）

public partial class Form1 : Form 
{ 
    Room ThisRoom = new Room(); 
    public Form1() 
    { 
     InitializeComponent();   
     this.Text = "Aquinas College Master Controller"; 
    } 

    private void roomDesignerToolStripMenuItem_Click(object sender, EventArgs e) 
    { 
     new RoomDesigner().Show(); 
    } 

    private void button1_Click(object sender, EventArgs e) 
    { 
     roomsToolStripMenuItem.DropDownItems.Clear(); 
     foreach (var Room in Global.Aquinas.Aquinas) 
     { 
      ToolStripMenuItem NewItem = new ToolStripMenuItem(Room.RoomID); 
      NewItem.Name = Room.RoomID; 
      NewItem.Click += new EventHandler(ItemClick); 
      roomsToolStripMenuItem.DropDownItems.Add(NewItem); 
     } 
    } 

    void ItemClick(object sender, EventArgs e) 
    { 
     ToolStripItem item = (ToolStripItem)sender; 
     label2.Text = item.Name; 
     foreach (var Room in Global.Aquinas.Aquinas) 
     { 
      if (Room.RoomID == item.Name) 
      { 
       ThisRoom = Room; 
       break; 
      } 
     } 
     Panel RoomPanel = ThisRoom.Panel; 
     RoomPanel.Size = new Size(607, 304); 
     RoomPanel.Location = new Point(144, 27); 
     RoomPanel.BackColor = Color.White; 
     this.Controls.Add(RoomPanel); 
    } 
} 

这是我的一些房间对象的代码。 （这是在Room.cs）

public class Room 
{ 

    private List<CtrlComputer> _Computers; 

    public List<CtrlComputer> Computers 
    { 
     get { return _Computers; } 
     set { _Computers = value; } 
    } 

    private string _RoomID; 

    public Room() 
    { 
     _Computers=new List<CtrlComputer>(); 
    } 

    public string RoomID 
    { 
     get 
     { 
      return _RoomID; 
     } 

     set 
     { 
      _RoomID = value; 
     } 
    } 

    public Panel Panel 
    { 
     get 
     { 
      return _Panel; 
     } 

     set 
     { 
      _Panel = value; 
     } 
    } 

    private Panel _Panel; 
} 

而这里是我注册了我刚刚把我的设计，以一个新的房间面板。 （这是我的一些RoomDesigner.cs的）

public partial class RoomDesigner : Form 
{ 
    Room NewRoom = new Room(); 
    Panel RoomDesignerPanel = new Panel(); 
    public RoomDesigner() 
    { 
     InitializeComponent(); 
     RoomDesignerPanel.Size = new Size(607, 304); 
     RoomDesignerPanel.Location = new Point(144, 27); 
     RoomDesignerPanel.BackColor = Color.White; 
     this.Controls.Add(RoomDesignerPanel); 
     textBox1.ForeColor = SystemColors.GrayText; 
     textBox1.Text = "Enter Computer ID Here"; 
     this.textBox1.Leave += new System.EventHandler(this.textBox1_Leave); 
     this.textBox1.Enter += new System.EventHandler(this.textBox1_Enter); 
     textBox2.ForeColor = SystemColors.GrayText; 
     textBox2.Text = "Enter Room ID Here"; 
     this.textBox2.Leave += new System.EventHandler(this.textBox2_Leave); 
     this.textBox2.Enter += new System.EventHandler(this.textBox2_Enter); 
    } 

    private void textBox1_Leave(object sender, EventArgs e) 
    { 
     if (textBox1.Text.Length == 0) 
     { 
      textBox1.Text = "Enter Computer ID Here"; 
      textBox1.ForeColor = SystemColors.GrayText; 
     } 
    } 

    private void textBox1_Enter(object sender, EventArgs e) 
    { 
     if (textBox1.Text == "Enter Computer ID Here") 
     { 
      textBox1.Text = ""; 
      textBox1.ForeColor = SystemColors.WindowText; 
     } 
    } 
    private void textBox2_Leave(object sender, EventArgs e) 
    { 
     if (textBox2.Text.Length == 0) 
     { 
      textBox2.Text = "Enter Room ID Here"; 
      textBox2.ForeColor = SystemColors.GrayText; 
     } 
    } 

    private void textBox2_Enter(object sender, EventArgs e) 
    { 
     if (textBox2.Text == "Enter Room ID Here") 
     { 
      textBox2.Text = ""; 
      textBox2.ForeColor = SystemColors.WindowText; 
     } 
    } 


    private void button1_Click(object sender, EventArgs e) 
    { 
     CtrlComputer NewComputer = new CtrlComputer(); 
     NewComputer.ComputerID = textBox1.Text; 
     NewComputer.Text = NewComputer.ComputerID; 
     NewComputer.Parent = RoomDesignerPanel; 
     RoomDesignerPanel.Controls.Add(NewComputer); 
     NewRoom.Panel = RoomDesignerPanel; 
     NewRoom.Add(NewComputer); 
    } 

当我尝试重新加载面板，该对象的RoomID返回罚款，但该面板是不是。有任何想法吗？

编辑：对不起，在我的岗位不明确的，第一职位并不容易。 该面板是在设计器中创建的，但我试过private Panel Panel1 = new Panel();，但没有运气。我目前的问题是，在Form1.cs中，程序将抛出“无法访问已处理的对象”，但我在这里遵循指南https://msdn.microsoft.com/en-us/library/82785s1h(v=vs.110).aspx。

Answer 1

你所希望做的是面板对象的集合之间的交换（有点像你自己的版本的TabPages的）。要做到这一点，你需要创建每个Panel对象（你可以在RoomDesigner中这样做，这很好，但有一个问题：请参阅下面的*）。手头上有这个集合，当你想在窗体上显示它时，你需要移除panel1创建的设计器代码（Controls.Remove（panel1））并插入新的（Controls.Add（RoomPanel））。

由于控制利用系统资源，确保处置您将不再使用任何控制。以下是一个示例方法：

//Initial case where no room has been displayed yet and panel1 is still valid 
    private Panel CurrentPanel = null; 

    public void SwapPanel(Panel p) 
    { 
     //If no panel has been placed yet, get rid of the default one 
     if (panel1 != null) 
     { 
      //we should never need the designer panel again, so dispose it 
      panel1.Dispose(); 
      this.Controls.Remove(panel1); 
     } 
     else 
     { 
      //we may return to this panel later, so don't dispose it 
      this.Controls.Remove(CurrentPanel); 
     } 
     CurrentPanel = p; 
     this.Controls.Add(p); 
    } 

当您最后关闭并且不再需要存储在您的Room集合中的面板时，请务必将其丢弃。 （但是，如果您的整个程序正在退出，那么它无关紧要，但无论如何都是最佳做法）

*当您关闭任何RoomDesigner窗体（或任何窗体）时，它包含在“控制'将被处置，即使你在别处使用它们。为防止出现这种情况，请在RoomDesigner Controls集合关闭之前删除要保留的控件。