这个简单的代码有什么问题？

我想比较下面的2个数组，并找出差异。键“主人”和“公司”的值是不同的，但是当我比较这些数组时，它表示只有“公司”值是不同的。但是，当我创建2个只有一个键/值对“主人”的新阵列时，它可以正常工作。我犯了一些错误吗？这个简单的代码有什么问题？

<?php 

$arr1 = Array 
    (
     "leadid" => "418176000000069007", 
     "smownerid" => "418176000000047003", 
     "lead owner" => "Amit Patil", 
     "company" => "SAM", 
     "first name" => "Test", 
     "last name" =>"Lead1", 
     "designation" => "call", 
     "email" => "", 
     "phone" => "958", 
     "fax" => "", 
     "mobile" => "", 
     "website" => "www.infosys.con", 
     "lead source" => "Cold Call", 
     "lead status" => "Contact in Future", 
     "industry" => "None", 
     "no of employees" => "45000", 
     "annual revenue" => "0", 
     "rating" => "Active", 
     "smcreatorid" => "418176000000047003", 
     "created by" => "Amit Patil", 
     "modifiedby" => "418176000000047003", 
     "modified by" => "Amit Patil", 
     "created time" => "2012-04-05 19:58:00", 
     "modified time" => "2012-05-02 08:51:08", 
     "street" => "", 
     "city" => "", 
     "state" => "", 
     "zip code" => "", 
     "country" => "", 
     "description" => "", 
     "skype id" => "", 
     "email opt out" => "false", 
     "salutation" => "Mr.", 
     "secondary email" => "" 
     ); 

$arr2 = Array 
    (
     "leadid" => "418176000000069007", 
     "smownerid" => "418176000000047003", 
     "lead owner" => "Amit aaa", 
     "company" => "SAM A", 
     "first name" => "Test", 
     "last name" => "Lead1", 
     "designation" => "call", 
     "email" => "", 
     "phone" => "958", 
     "fax" => "", 
     "mobile" => "", 
     "website" => "www.infosys.con", 
     "lead_source" => "Cold Call", 
     "lead_status" => "Contact in Future", 
     "industry" => "None", 
     "no_of_employees" => "45000", 
     "annual_revenue" => "0", 
     "rating" => "Active", 
     "smcreatorid" => "418176000000047003", 
     "created_by" => "Amit Patil", 
     "modifiedby" => "418176000000047003", 
     "modified_by" => "Amit Patil", 
     "created_time" => "2012-04-05 19:58:00", 
     "modified_time" => "2012-05-02 08:51:08", 
     "street" => "", 
     "city" => "", 
     "state" => "", 
     "zip_code" => "0", 
     "country" => "", 
     "description" => "", 
     "skype_id" => "", 
     "email_opt_out" => "false", 
     "salutation" => "Mr.", 
     "secondary_email" => "" 
     ); 

$arr3 = array("lead owner" => "Amit Patil"); 
$arr4 = array("lead owner" => "Amit aaa"); 

print_r(array_diff($arr1,$arr2)); 
echo "<br>"; 
print_r(array_diff($arr3,$arr4)); 
?>

输出是如下

Array ([company] => SAM) 
Array ([lead owner] => Amit Patil)

来源

2012-05-25 www.amitpatil.me

的输出是什么？ – AlphaMale

添加了输出。 –

也添加了你想要的输出。意味着你想要的输出是什么？ – AlphaMale

如果要在关联数组之间进行区分，以便键值对非常重要，而不仅仅是值，请使用array_diff_assoc而不是array_diff。

来源

2012-05-25 05:31:39

它返回了一些错误的结果，我的意思是它返回的几列不是不同的前缀：“no_of_employees”，“annual_revenue”，“created_by” “CREATED_TIME”。此键的值完全相同。为什么会这样？ –

看起来你的一些键正在使用空格，有些使用下划线。 –

尝试复制上面的代码...没有下划线。它也返回错误的结果。 –

你错误地理解它。

的array_diff文档页面说

返回包含所有从ARRAY1不在存在于任何其他阵列的条目的阵列。

但Amit Patil存在于第二阵列因此它返回只有一个值，它是在SAM和它只有一个值，它不存在于第二阵列。

来源

2012-05-25 05:30:55

Shakti，谢谢你的解释，现在我明白了addta_diff（）和array_diff_assoc（）之间的差异 –

array_diff()返回互补值。所以你可以这样做：

array_diff(array_merge($arr1, $arr2), array_intersect($arr1, $arr2));

这样它会工作。

来源

2012-05-25 05:33:53

发生这种情况是因为“array_diff”函数返回第一个数组中任何键的值，而不是第二个数组中的任何键都不会发生。

lead_owner“Amit Patil”不等于第二个数组lead_owner，但等于第二个数组的created_by和modified_by键。

您应该为此使用“array_diff_assoc”。

来源

2012-05-25 05:35:26 jfoliveira

试试这个，看看，这应该工作

print_r(array_diff_assoc($arr1,$arr2)); 
echo "<br>"; 
print_r(array_diff_assoc($arr3,$arr4));

来源

2012-05-25 05:35:43 Wazan

这个简单的代码有什么问题？

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