SQL - 1个父表，2个表 - 每个行中的子表中返回一行

Question

表A

• PARENTID
• 名称

表B

• BKey
• PARENTID
• DescB

表C

• CKEY
• PARENTID
• DescC

我需要返回1行进行数据的每个组合排在B/A tha t匹配父ID，并且如果其中一个子表的行数多于另一个，则应为该描述使用空值返回一行。

例如，如果该数据是如下

表A

1 FirstParent 
2 Second Parent 

表B

1 1 BDesc1 
2 1 BDesc2 
3 2 P2BDesc1 

表C

1 1 CDesc1 
2 2 P2CDesc1 
3 2 P2CDesc2 

如果我找回基于FirstParent，结果应该是：

1 FirstParent BDesc1 CDesc1 
1 FirstParent BDesc2 NULL 

如果我找回基于SecondParent，结果应该是：

2 SecondParent P2BDesc1 P2CDesc1 
2 SecondParent NULL  P2CDesc2 

反正有这样做没有的有工会吗？

Answer 1

declare @ParentID int 
set @ParentID = 1 

select a.name, 
     bc.descb, 
     bc.descc 
from TableA as a 
    cross join (select b.descb, 
        c.descc 
       from (select *, 
          row_number() over(order by b.bkey) as rn 
         from TableB as b 
         where b.parentid = @parentid) as b 
       full outer join 
        (select *, 
          row_number() over(order by c.ckey) as rn 
         from TableC as c 
         where c.parentid = @parentid) as c 
        on b.rn = c.rn) as bc 
where a.parentid = @parentid 

试试这里：http://data.stackexchange.com/stackoverflow/qt/112538/

编辑：使用ExternalKey查询多个PARENTID的

建议指标的版本：

create index IX_B_ParentID on TableB(ParentID) include (DescB) 
create index IX_C_ParentID on TableC(ParentID) include (DescC) 

我会创建包含相匹配的ExternalKey的PARENTID的，然后用这个来代替表变量查询中的TableA。

declare @ExternalKey int = 1 

declare @T table(ParentID int primary key, Name varchar(20)) 
insert into @T (ParentID, Name) 
select ParentID, NAme 
from TableA 
where ExternalKey = @ExternalKey 


select a.name, 
     bc.descb, 
     bc.descc 
from @T as a 
    inner join (select b.descb, 
        c.descc, 
        coalesce(b.ParentID, c.ParentID) as ParentID 
       from (select b.ParentID, 
          b.DescB, 
          row_number() over(partition by b.ParentID order by b.bkey) as rn 
         from TableB as b 
         where b.parentid in (select ParentID from @T)) as b 
       full outer join 
        (select c.ParentID, 
          c.DescC, 
          row_number() over(partition by c.ParentID order by c.ckey) as rn 
         from TableC as c 
         where c.parentid in (select ParentID from @T)) as c 
        on b.rn = c.rn and 
        b.ParentID = c.ParentID) as bc 
    on a.ParentID = bc.ParentID 

Answer 2

可以在2个步骤实现：

1）每一个孩子表中计算的记录数。

2）加入从第一步

select a.ParentId, a.Name, b.DescB, c.DescC 
from (
    select ParentId, (select count(*) from b where a.ParentId = b.ParentId) as cntB, 
    (select count(*) from c where a.ParentId = b.ParentId) as cntC 
from a 
left join b cntB >= cntC and a.ParentId = b.ParentId 
left join c cntB < cntC and a.ParentId = c.ParentId 

Answer 3

就到的记录数，我是真的希望这是MSSQL问题

declare @a table(
ParentID int, 
Name varchar(15)) 

declare @b table(
BKey int, 
ParentID int, 
DescB varchar(10)) 


declare @c table(
CKey int, 
ParentID int, 
DescC varchar(10)) 

insert @a values (1,'FirstParent') 
insert @a values (2,'SecondParent') 

insert @b values(1, 1, 'BDesc1') 
insert @b values(2, 1, 'BDesc2') 
insert @b values(3, 2, 'P2BDesc1') 

insert @c values(1, 1, 'CDesc1') 
insert @c values(2, 2, 'P2CDesc1') 
insert @c values(3, 2, 'P2CDesc2') 

;with b as 
(
    select DescB, ParentID, row_number() over (partition by parentid order by DescB) rn from @b 
), 
c as 
(
    select DescC, ParentID, row_number() over (partition by parentid order by DescC) rn from @c 
), 
d as (
    select DescB, DescC, coalesce(b.parentid, c.parentid) parentid from b 
    full outer join c 
    on c.parentid = b.parentid and c.rn = b.rn 
) 
select a.ParentID, a.Name, d.DescB, d.DescC from @a a 
join d 
on a.parentid = d.parentid 
order by 1 

尝试在这里第一或第二个表： http://data.stackexchange.com/stackoverflow/q/112537/