多个在不同时间

Question

我试图把在三个不同的LED，但我希望他们关闭在不同的时间，但这个看起来不可能的LED ....：哭： 这里是我的代码：

import RPi.GPIO as GPIO 
import time from threading 
import Thread 
def led1(): 
GPIO.setmode(GPIO.BOARD) 
GPIO.setup(36, GPIO.OUT) 
GPIO.output(36,1) 
time.sleep(3) 
GPIO.output(36,0) 
GPIO.setwarnings(False) 
def led2(): GPIO.setmode(GPIO.BOARD) 
GPIO.setup(38, GPIO.OUT) 
GPIO.output(38,1) 
time.sleep(5) 
GPIO.output(38,0) 
GPIO.setwarnings(False) 
def led3(): 
GPIO.setmode(GPIO.BOARD) 
GPIO.setup(40, GPIO.OUT) 
GPIO.output(40,1) 
time.sleep(7) 
GPIO.output(40,0) 
GPIO.setwarnings(False) 
thread1= Thread(target = led1) 
thread2= Thread(target = led2) 
thread3= Thread(target = led3) 
thread1.run() thread2.run() 
thread3.run() 
##thread1.join() // not sure if I have to put that or not 
##thread2.join() 
##thread3.join() 
GPIO.cleanup() 

Answer 1

为什么不做这样的事情？

import RPi.GPIO as GPIO 
import time 

GPIO.setmode(GPIO.BOARD) 
GPIO.setup(36, GPIO.OUT) 
GPIO.setup(38, GPIO.OUT) 
GPIO.setup(40, GPIO.OUT) 
GPIO.setwarnings(False) 

GPIO.output(36,1) 
GPIO.output(38,1) 
GPIO.output(40,1) 

time.sleep(3) 
GPIO.output(36,0) 
time.sleep(2) 
GPIO.output(38,0) 
time.sleep(2) 
GPIO.output(40,0) 

GPIO.cleanup() 

编辑：如果你不知道的时候每个LED将是对：

import RPi.GPIO as GPIO 
import time 

GPIO.setmode(GPIO.BOARD) 
GPIO.setup(36, GPIO.OUT) 
GPIO.setup(38, GPIO.OUT) 
GPIO.setup(40, GPIO.OUT) 
GPIO.setwarnings(False) 

led1time = 3 
led2time = 5 
led3time = 7 
m = max(led1time, led2time, led3time) 

GPIO.output(36,1) 
GPIO.output(38,1) 
GPIO.output(40,1) 

t = 0 
while t <= m: 
    if t >= led1time: 
     GPIO.output(36,0) 
    if t >= led2time: 
     GPIO.output(38,0) 
    if t >= led3time: 
     GPIO.output(40,0) 
    time.sleep(0.1) 
    t += 0.1 

GPIO.cleanup() 

您现在可以设置每个LED多久会在与0.1秒准确性，你可以通过用较低的数字替换任何出现的0.1来提高精度。