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是python中的新手。提取下面的代码从在线帖子登录到网站,但出现错误。如何修复这个执行登录网站的python代码
请帮忙解决这个问题,并说明将帮助我
import requests
with requests.Session() as c:
EMAIL = '[email protected]'
PASSWORD = '[email protected]'
URL = 'https://www.linkedin.com/'
c.get(URL)
token = c.cookies['CsrfParam']
# This is the form data that the page sends when logging in
login_data = {loginCsrfParam:token, session_key:EMAIL, session_password:PASSWORD}
# Authenticate
r = c.post(URL, data=login_data)
# Try accessing a page that requires you to be logged in
r = c.get('https://www.linkedin.com/feed/')
print r.content
我坚持下面的错误:
C:\Python27>python website.py
Traceback (most recent call last):
File "website.py", line 8, in <module>
token = c.cookies['CsrfParam']
File "C:\Python27\lib\site-packages\requests\cookies.py", line 329, in __getitem__
return self._find_no_duplicates(name)
File "C:\Python27\lib\site-packages\requests\cookies.py", line 400, in _find_no_duplicates
raise KeyError('name=%r, domain=%r, path=%r' % (name, domain, path))
KeyError: "name='CsrfParam', domain=None, path=None"
嗨!我跑出它令牌。它没有显示任何错误,但它并没有打开网页。我希望此代码打开网页并使用提供的凭据登录。 –
我已经尝试了很多与请求的变化,我不能得到它的工作。根据我的经验,Selenium倾向于使用反编程系统,因此可能需要查看此文章:https://www.quora.com/How-do-I-log-into-Quora-using-Python-since-they -dont-have-an-API。另外还有一个Quora模块:https://pypi.python.org/pypi/quora/但是这不会登录,所以它可能没有你需要的功能。对不起,我忍不住了。 – TLOwater