SQL从另一行匹配查询

Question

这里寻找以前的日期是我所接合的两个表...

song_id song_name 
    51 | Song Name A 
    368 | Song Name B 
    168 | Song Name C 
    568 | Song Name D 
    13 | Song Name E 


song_id | song_order|  show_date  |show_id 
368  |  1  | 2010-02-17 00:00:00 | 367  
368  |  0  | 2012-04-06 00:00:00 | 499 
51  |  2  | 2012-01-19 00:00:00 | 399 
51  |  2  | 2013-04-24 00:00:00 | 870 
51  |  8  | 2013-07-19 00:00:00 | 899 
368  |  2  | 2013-07-19 00:00:00 | 899 
13  |  5  | 2013-07-19 00:00:00 | 899 
568  |  2  | 2013-07-19 00:00:00 | 899 
368  |  4  | 2012-06-08 00:00:00 | 799 
168  |  2  | 2013-06-28 00:00:00 | 896 
568  |  2  | 2013-07-03 00:00:00 | 897 
568  |  2  | 2010-02-21 00:00:00 | 897 

我已经制定了什么，我试图在SQL小提琴link但我无法获得正确的代码。我试图基于show_id的值说'899'，返回所有行等于899，show_ids都有相同的日期分配给他们，但基于歌曲ID我想返回的前一个日期，song_id过来。

我想将数据返回...

SHOW_DATE | SHOW_ID | SONG_NAME | SONG_ID |  PREVDATE 
July, 19 2013 |  899 | Song Name A |  51 | April, 24 2013 
July, 19 2013 |  899 | Song Name B |  368 | April, 08 2012 
July, 19 2013 |  899 | Song Name E |  13 | FIRST TIME 
July, 19 2013 |  899 | Song Name D |  568 | July, 03 2013 

我在这里的代码七月前才刚刚返回前一个日期，19到2013年，这是七月03 2013和推杆，每PrevDate。任何人都可以帮我吗？我不是最有经验的编码人员，我相信我不能做我在这里所做的，因为我正在编组一个子查询。先谢谢了！

SELECT tbl_shows.show_date, tbl_shows.show_id, 
tbl_songs.song_name, tbl_shows.song_id, (
    SELECT 
     MAX(show_date) 
    FROM tbl_shows AS fdate 
    WHERE tbl_shows.show_date > show_date 
) As PrevDate 
    FROM tbl_shows LEFT JOIN tbl_songs 
    ON tbl_shows.song_id = tbl_songs.song_id 
    WHERE tbl_shows.show_id = 899 

Answer 1

试试这个...

SELECT a.show_date, a.show_id, 
    b.song_name, a.song_id, (
    SELECT 
    MAX(show_date) 
    FROM tbl_shows AS c 
    WHERE a.show_date > c.show_date and a.song_id = c.song_id 
) As PrevDate 
    FROM tbl_shows a, tbl_songs b 
    WHERE a.song_id = b.song_id 
    AND a.show_id = 899 

Answer 2

看起来像你只需要告诉MySQL按日期对结果：

SELECT tbl_shows.show_date, tbl_shows.show_id, 
tbl_songs.song_name, tbl_shows.song_id, (
    SELECT 
     MAX(show_date) 
    FROM tbl_shows AS fdate 
    WHERE tbl_shows.show_date > show_date 
) As PrevDate 
FROM tbl_shows LEFT JOIN tbl_songs 
ON tbl_shows.song_id = tbl_songs.song_id 
GROUP BY tbl_shows.show_date 
HAVING tbl_shows.show_id = 899 

编辑：或者，如丹Bracuk指出的那样，你可以这样做：

SELECT tbl_shows.show_date, tbl_shows.show_id, 
tbl_songs.song_name, tbl_shows.song_id, (
    SELECT 
     MAX(show_date) 
    FROM tbl_shows AS fdate 
    WHERE tbl_shows.show_date > show_date 
) As PrevDate 
FROM tbl_shows 
LEFT JOIN tbl_songs 
ON tbl_shows.song_id = tbl_songs.song_id 
WHERE tbl_shows.show_id = 899 
GROUP BY tbl_shows.show_date 
ORDER BY tbl_shows.show_id DESC 
LIMIT 0, 10 

注意：最后两行比其他任何内容都更多。