Android中的Flickr JSON解析

Question

我想从这个URL解析JSON（http://api.flickr.com/services/feeds/photos_public.gne?format=json），但文档实际上返回了无效的JSON。见

 jsonFlickrFeed({ 
     "title": "Uploads from everyone", 
     "link": "http://www.flickr.com/photos/", 
     "description": "", 
     "modified": "2012-11-26T18:27:41Z", 
     "generator": "http://www.flickr.com/", 
     "items": [ 
     { 
      "title": "2012 Thanksgiving Holiday Weekend", 
      "link": "http://www.flickr.com/photos/agape_boarding_school/8220697785/", 
      "media": {"m":"http://farm9.staticflickr.com/8478/8220697785_bb298ac5b3_m.jpg"}, 
      "date_taken": "2012-11-24T14:19:21-08:00", 
      "description": " <p><a href=\"http://www.flickr.com/people/agape_boarding_school/\">Agape Boarding School<\/a> posted a photo:<\/p> <p><a href=\"http://www.flickr.com/photos/agape_boarding_school/8220697785/\" title=\"2012 Thanksgiving Holiday Weekend\"><img src=\"http://farm9.staticflickr.com/8478/8220697785_bb298ac5b3_m.jpg\" width=\"240\" height=\"159\" alt=\"2012 Thanksgiving Holiday Weekend\" /><\/a><\/p> <p>Great Day at Agape Boarding School<\/p>", 
      "published": "2012-11-26T18:27:41Z", 
      "author": "nobody@flickr.com (Agape Boarding School)", 
      "author_id": "36563683@N07", 
      "tags": "school boarding agape" 
     }, ... 

我想让我的分析器是尽可能通用那么，什么是更好的方式来删除“jsonFlickrFeed（”文档的一部分，只与JSON它自身工作？

public class JSONParser extends AsyncTask <String, Void, JSONObject> { 

static InputStream is = null; 
static JSONObject jObj = null; 
static String json = ""; 

// constructor 
public JSONParser() { 

} 

@Override 
protected JSONObject doInBackground(String... params) { 
    String url=params[0]; 

    // Making HTTP request 
    try { 
     // defaultHttpClient 
     DefaultHttpClient httpClient = new DefaultHttpClient(); 
     HttpPost httpPost = new HttpPost(url); 

     HttpResponse httpResponse = httpClient.execute(httpPost); 
     HttpEntity httpEntity = httpResponse.getEntity(); 
     is = httpEntity.getContent();   

    } catch (UnsupportedEncodingException e) { 
     e.printStackTrace(); 
    } catch (ClientProtocolException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 

    try { 
     BufferedReader reader = new BufferedReader(new InputStreamReader(
       is, "iso-8859-1"), 8); 
     StringBuilder sb = new StringBuilder(); 
     String line = null; 
     while ((line = reader.readLine()) != null) { 
      sb.append(line + "\n"); 
     } 
     is.close(); 
     json = sb.toString(); 
    } catch (Exception e) { 
     Log.e("Buffer Error", "Error converting result " + e.toString()); 
    } 

    // try parse the string to a JSON object 
    try { 
     jObj = new JSONObject(json); 
    } catch (JSONException e) { 
     Log.e("JSON Parser", "Error parsing data " + e.toString()); 
    } 

    // return JSON String 
    return jObj; 
} 

}

Answer 1

正如你所说，你只会有你解析它之前删除字符串的这一部分。

如果你想成为更普遍的，你可以搜索第一{ char并删除它之前的所有内容，并删除最后的} char，并删除它后面的所有内容。但是这仍然不能确保输入有效。

Answer 2

我已经通过给定的方式解决了这个问题。

Flickr的旧的Web API是：http://api.flickr.com/services/feeds/photos_public.gne?id=xxxxxxxx&lang=en-us&format=json

的Flickr最新的Web API是：http://api.flickr.com/services/feeds/photos_public.gne?id=xxxxxxxx&lang=en-us&format=json&nojsoncallback=1

使用最新的一个网络API。

更换您用户ID，而不是XXXXXXXX。

希望它对你有帮助。