报价标签的正则表达式PHP - 一般情况下

Question

我问的问题关于正则表达式替换引用，不带引号，引用，不带引号的......在这个线程情况：Regex for quote tags php

我意识到我需要保存的物品订购更一般的情况。如引用，不加引号，引用，引用，引用等等......还有没有嵌套引号。我想它应该做迭代或递归...我会解释一下例子。

some unquoted text11 
[quote="person1"]some quoted text11[/quote] 
[quote="person2"]some quoted text22[/quote] 
[quote="person3"]some quoted text33[/quote] 
some unquoted text22 
... 
[quote="person4"]some quoted text44[/quote] 
... 

结果数组应该是：

Array //PRESERVED ORDER 
     (
      [0] => Array 
       (
        ['type'] => unquoted 
        ['name'] => '' 
        ['text'] => some unquoted text11 
       ) 
      [1] => Array 
       (
        ['type'] => quoted 
        ['name'] => person1 
        ['text'] => some quoted text11 
       ) 
      [2] => Array 
       (
        ['type'] => quoted 
        ['name'] => person2 
        ['text'] => some quoted text22 
       ) 
      [3] => Array 
       (
        ['type'] => quoted 
        ['name'] => person3 
        ['text'] => some quoted text33 
       ) 
      [4] => Array 
       (
        ['type'] => unquoted 
        ['name'] => '' 
        ['text'] => some unquoted text22 
       ) 

       ... 

      [5] => Array 
       (
        ['type'] => quoted 
        ['name'] => person4 
        ['text'] => some quoted text44 
       ) 

       ... 
     } 

Answer 1

正则表达式是解决这个问题的一个不错的选择，因为他们不请保持状态的能力。您提到嵌套时所指的那种状态。即使对于不允许嵌套标签的简单方法，解决方案仍然依赖于了解表达式的状态，因为您希望根元素被标识为（，对于您期望的数组中的第一个元素）。

相反，更好的解决方案是使用已经证明的快速单通解析器，如BBcode，它可以做更有效的工作并提供更多可维护的代码。