您的SQL语法有错误;检查对应于您MariaDB的服务器

Question

手册我有这样的代码：

ANZ=`mysql -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "SELECT count(id) FROM $TABLE WHERE deleted=1 and not lastname='anonym';" --skip-column-names -B;`; 
if [ $((ANZ)) -gt 0 ] 
then 
mysql -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "SELECT id, username FROM $TABLE WHERE deleted=1 and not lastname='anonym' and username like '%@%';" --skip-column-names -B > $FILE; 

cat $FILE | while read TMP 

do 
echo "temp:" ${TMP% *}; 

    UserID=${TMP% *}; 
    echo $UserID >> $RES_FILE; 

    echo "User $UserID wird anonymisiert..."; 
echo $UserID; 

echo '`mysql -u$USER -p$PASSWD -h$HOST -D $DATABASE -e "UPDATE $TABLE SET username="'$A$UserID'", email='a@nonym.de', firstname='$A', lastname='$A', icq='', skype='', yahoo='', aim='', msn='', phone1='', phone2='', institution='', dep$ 
echo'  `mysql -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "UPDATE mdl_message SET subject='Neue Mitteilung von anonym' WHERE useridfrom=$UserID;"`'; 
echo'  `mysql -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "UPDATE mdl_message_read SET subject='Neue Mitteilung von anonym' WHERE useridfrom=$UserID;"`'; 
    VNAME=`mysql -N -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "SELECT firstname FROM $TABLE WHERE id=$UserID;"`; 
    NNAME=`mysql -N -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "SELECT lastname FROM $TABLE WHERE id=$UserID;"`; 
    `mysql -u $USER -p$PASSWD -h$HOST -D $DATABASE -e "UPDATE mdl_event SET name='Meeting with your Student, anonym' WHERE name LIKE 'Meeting with your Student,%$VNAME $NNAME%';"`; 

done 
echo 
"Finish!" 

而我得到的错误是：

的mysql -u $ USER $ -p -h PASSWD $ HOST -D $ DATABASE -e“UPDATE $ TABLE SET username =”anonym611 demo@XXXX.de.1456411291“，email=a@nonym.de，firstname = anonym，lastname = anonym，icq =，skype =，yahoo =， aim =，msn =，phone1 =，phone2 =，institution =，department =，address =，city =，country =，url = WHERE deleted = 1 AND id = 611 demo@XXXXX.de.1456411291;“ ./anonym.sh：Zeile 50：echo
mysql -u $ USER -p $ PASSWD -h $ HOST -D $ DATABASE -e“UPDATE mdl_message SET subject = Neue：command not found。 ./anonym.sh ：Zeile 52：echo`mysql -u $ USER -p $ PASSWD -h $ HOST -D $ DATABASE -e“UPDATE mdl_message_read SET subject = Neue：command not found。

错误1064（42000）在第1行：您的SQL语法有错误;请检查与您的MariaDB服务器版本对应的手册，以获取在第1行“demo@xxxxxxx.de.1456411291”附近使用的正确语法。

错误1064（42000）在第1行：您的SQL语法错误;检查对应于您MariaDB的服务器版本在线路附近使用“demo@xxxxxxxxxx.de.1456411291”正确的语法手册1个

Answer 1

您的SQL错误是在这里：

[...] WHERE deleted=1 AND id=611 demo@XXXXX.de.1456411291;" 

你要么需要在id=611之后关闭sql查询，或者您的id是611 demo@XXXXX.de.1456411291，在这种情况下，您需要在其周围添加"。 @Bern Buffen答案后

编辑：

你一定要逃逸查询的每个"：

echo 'mysql -u$USER -p$PASSWD -h$HOST -D $DATABASE -e "UPDATE $TABLE SET username=\"$A$UserID\", email=\"a@nonym.de\", firstname=\"$A\", lastname=\"$A\", icq='', skype='', yahoo='', aim='', msn='', phone1='', phone2='', institution='', department='', address='', city='', country='', url='' WHERE deleted=1 AND id=\"$UserID\";"'; 

Answer 2

你不能在带引号的字符串使用Quirles。使用单引号或反斜杠转义

=“anonym611 demo@XXXXX.de.1456411291”