如何获得具有更好性能的重复值的行

Question

我需要获取在列中具有重复值的行。这是SQL：

select * from `match` where `match`.`homeTeam` in 
(select `matchView`.`homeTeam` from `matchView` 
group by `matchView`.`homeTeam` having (count(0) > 1)) 
order by `match`.`homeTeam` 

它完成这项工作，但需要15秒。我能做些什么来提高它的速度

编辑：解释SQL结果：

id select_type  table type possible_keys key  key_len  ref  rows Extra 
1 PRIMARY  match ALL  NULL NULL NULL NULL 2691 Using where; Using filesort 
2 DEPENDENT SUBQUERY match ALL  NULL NULL NULL NULL 2691 Using where; Using temporary; Using filesort 

Answer 1

select `match`.* 
from `match` join (select `matchView`.`homeTeam` 
        from `matchView` 
        group by `matchView`.`homeTeam` 
        having (count(0) > 1)) watches ON `match`.`homeTeam`=watches.`homeTeam` 
order by `match`.`homeTeam`