0
我使用这个脚本,以消除在Perl无效搜索字词删除无效搜索字词,我在Windows上运行,我无法找到的 兼容版本:的Perl从字符串
Lingua::EN::StopWordList
Lingua::StopWords qw(getStopWords)
我有一个停止词的数组,但是一旦我使用下面的REGEX,我就会失去导致词语冲突的关键空格。 请注意,Stop-Word数组中的每个单词都有两个空格,一个在右侧,一个在左侧。
如何在不丢失关键空白的情况下有效移除停用词?
use strict;
use warnings;
use utf8;
use IO::File;
use String::Util 'trim';
my $inFile = "C:\\Users\\David\\Downloads\\InfoRet\\Explore the ways to get better grades.txt";
my $inFh = new IO::File $inFile, "r";
my $lineNum = 0;
my $line = undef;
my $loc = undef;
my $str = undef;
my @stopList = (" the ", " a ", " an ", " of ", " and ", " on ", " in ", " by ", " with ", " at ", " after ", " into ", " their ", " is ", " that ", " they ", " for ", " to ", " it ", " them ", " which ");
for(my $i = 1; $i <= 4; $i++) {
<$inFh>
}
while($line = <$inFh>) {
$lineNum++;
chomp $line;
$line =~ s/[\$#@~!&*()\[\];.,:?^`\\\/]+//g;
for my $planet (@stopList) {
$loc = index($line, $planet);
if($loc!=(-1)) {
#$line =~ s/$str//g;
$line =~ s/$planet//g;
}
}
print "$line\n";
}
一个想法是不删除空白。而不是循环停止列表,使用停用词作为键和它们的值''“'做一个散列。然后执行#(\ w +)#$ hash {lc($ 1)} // $ 1#g'注意你必须使用defined或'//',因为'“”'是一个假值。另请注意,您必须从停用词列表中删除空格。 – TLP 2014-11-08 18:24:29