如何从一个函数值传递到另一个在C＃

Question

我有一个函数

 private void button_Click(object sender, RoutedEventArgs e) 
     { 
     random(); 

     } 

     private void random() 
     { 
     //other code 
     ImageBrush background = new ImageBrush(); 
     background.ImageSource = new System.Windows.Media.Imaging.BitmapImage(new       Uri(actorUri, UriKind.Relative)); 
     //other code 
     } 

我要访问按钮的点击功能背景变量 请告诉我如何访问...

Answer 1

private void button_Click(object sender, RoutedEventArgs e) 
    { 
    random(); 
    background.SomeMethod(); 

    } 

    ImageBrush background = new ImageBrush(); 

    private void random() 
    { 
    //other code 

    background.ImageSource = new System.Windows.Media.Imaging.BitmapImage(new       Uri(actorUri, UriKind.Relative)); 
    //other code 
    } 

编辑：

OR

private void button_Click(object sender, RoutedEventArgs e) 
    { 
    ImageBrush bg = random(); 
    bg.SomeMethod() 


    } 



    private ImageBrush random() 
    { 
    //other code 
    ImageBrush background = new ImageBrush(); 
    background.ImageSource = new System.Windows.Media.Imaging.BitmapImage(new       Uri(actorUri, UriKind.Relative)); 
    //other code 
    return background; 
    } 

Answer 2

你的问题不清楚，你的意思是？

private ImageBrush m_Background = new ImageBrush(); 

private void button_Click(object sender, RoutedEventArgs e) 
{ 
    // If actorUri is stored in a TextBox, for example... 
    random(textbox1.Text); 
} 

private void random(String actorUri) 
{ 
    // ... 
    m_Background = new ImageBrush(); 
    m_Background.ImageSource = new BitmapImage(new Uri(actorUri, UriKind.Relative)); 
    // ... 
} 

Answer 3

为什么不让background成为周围类的实例变量？

Answer 4

我不确定，但它听起来像你问这个。

private void button_Click(object sender, RoutedEventArgs e) 
    { 
     random(); 
     background.DoSomething(); 
    } 

    ImageBrush background ; 
    private void random() 
    { 
     //other code 
     background = new ImageBrush(); 
     background.ImageSource = new System.Windows.Media.Imaging.BitmapImage(new       Uri(actorUri, UriKind.Relative)); 
     //other code 
    } 

Answer 5

private void button_Click(object sender, RoutedEventArgs e) 
{ 
    ImageBrush background = random(); 
} 

private ImageBrush random() 
{ 
    //other code 
    ImageBrush background = new ImageBrush(); 
    background.ImageSource = new System.Windows.Media.Imaging.BitmapImage(new       Uri(actorUri, UriKind.Relative)); 
    return background; 
}