2013-05-02 86 views
2

我创建了一个哈希表,但我似乎被困在一个问题。我有散列表中的数据,并在搜索数据时按预期返回。但是,如果我搜索的东西不在表格中,但仍然存在于存在的元素中,它不会返回false。Java的哈希表搜索功能

例如:我有你好在我的哈希表的关键,可以说件15然后我做世界搜索和杂凑一样你好,只是举例。

我希望我的代码做的是返回NULL,因为即使键的散列一样,他们是不相等的。但是,我的代码如下,将返回键/数据(记录),而不是。

@SuppressWarnings("rawtypes") 
public Record search(T k) { 
    int i = hash(k);//Assign the computed hash value (combination of Record Class hashCode and Table's hash function above) to i. 
    if (a[i] == null || a[i].record.equals(k)) { 
     return null; 
    } else if (!a[i].record.equals(i) && a[i].record.getKey() != k) {//otherwise, the record is found and if the key stored does not equal the key being searched return null 
     return a[i].record; 
    } else { //otherwise the record is not the first record in the linked list 
     cursor = a[i]; //set cursor to equal the entire list of records sorted a the hash key reference 
     if (cursor.record.getKey() != k) { //if the key at cursor.record does not equal key (k), then move onto the cursor.next 
      return cursor.next.record; 
     } 
    } 
    return null; 
} 

Record类

public class Record<T, U> { 

private T key;//Contacts name, and the value that is ultimately hashed. It is then inserted, searched and deleted 
private U data;//This data is the Contacts address, when the key is hashed, nothing is done to this value except that it is 
//either stored or retrieved from the hash table when the key is used 

public T getKey() { 
    return key;//returns the value stored as a key 
} 

public void setKey(T k) { 
    this.key = k;//used during the insert operation to set key's value. 
} 

public U getData(T k) {//retrieve the data that is stored with an associated key that has been updated, searhed or is being written to a file 
    return data; 
} 

public void setData(U data) {//adds the data to the records data element 
    this.data = data; 
} 

public int hashCode(T k) {//When this hash code function is called, it returns a mathematical representation of the key, that was passed to it 
    //it returns the absolute value of the generic hashCode() function. Further computations are required in the Table class, since the hash created here 
    //can be very large and would throw and exception. For example, the hash for "Chris" after this computation has been performed is 94639767, which is 
    //much larger than our array. So this will cause an IndexOutOfBoundsException(). 
    return Math.abs(k.hashCode()); 
} 

public boolean equals(Record<T, U> r) { 
    //this equals method, doesn't override the generic equals() method provided by Java. Instead, this method is created to use instead of the generic 
    //equals method. When this is called, the has value computed above, with the additional math from the Table class, is compared to all of the elements 
    //in the array. If a match is found, this returns true 
    return key.equals(r.key); 
} 
} 
+0

我希望你这样做是作为一个练习,而不是在一个真正的应用程序中使用。如果是后者,则应该强烈考虑使用库HashMap类。 – 2013-05-02 20:20:25

+0

我只是想了解Java为我们提供的背景...... – Chris 2013-05-02 20:25:15

回答

4

这是一个经典的== VS .equals()的问题。而a[i].record.getKey().equals(k)也是如此

a[i].record.getKey() != k可以实现的。

你应该使用的(!a[i].record.getKey().equals(k))代替a[i].record.getKey() != k

+0

非常感谢!我以为我在今天的某个时候尝试过,但显然没有。我必须等几分钟才能将其标记为答案... – Chris 2013-05-02 20:15:07