从外部文件访问功能bash

Question

这非常简单，但由于我仍然是shell脚本中的新生代，我无法做到这一点。很简单，我有一个菜单驱动的脚本，当用户输入他的选择时，我循环使用case函数并执行选定的菜单。 Uptil现在我正在用相同的脚本编写完整的代码。现在我将代码放在外部脚本的每个菜单选项中，并从那里访问代码。因此，它是这样的，

#!/bin/bash 
. course_func 
file=names.dat 
[ ! -f $file ] && > $file 
while true 
do 
clear 
echo ------------------------------------------ 
echo 1. Create a record 
echo 2. View Records 
echo 3. Search for records 
echo 4. Delete records that match a pattern 
echo ------------------------------------------ 
echo "Please enter your choice or enter (q) to quit: \c ";read choice 
case $choice in 
    1) 
    create() 
    echo Enter to continue; read junk 
    ;; 
     *) 
    clear 
    echo Wat nonsense enter properly 
    echo Enter to continue: ;read crap 
    ;; 
esac 
done 

然后，我创建，我写的创建（）函数

代码是在链路另一外部脚本，

create() 
{ 
    while true 
    do 
     echo Please enter the name: ;read name 
     echo Please enter your surname: ;read surname 
     echo Please enter the address: ;read add 
     echo Please enter the cell no.: ;read cell 
     if yesno Do you really wish to save the following data to file 
     then 
     echo $name:$surname:$add:$cell >> $file 
     clear 
     echo The record has been inserted :D 
     else 
     echo The record was not save 
     fi 
     if yesno Do you wish to enter another record 
     then 
     : 
     else 
     xit 
     fi 
    done 
} 

addRecord() 
{ 

} 

search() 
{ 

} 

delRecord() 
{ 

} 

，但我得到一个错误，

course_func: line 31: syntax error near unexpected token `}' 
course_func: line 31: `}' 
menu_driven: line 18: syntax error near unexpected token `echo' 
menu_driven: line 18: ` echo Enter to continue; read junk' 

31行是我在哪里结束addRecord函数，它是空函数，f或其余案件。我们可以在bash中没有空的函数吗？

Answer 1

函数不能为空！

- Advanced Bash-Scripting Guide: Chapter 24. Functions

相反，尝试：

addRecord() 
{ 
    return 
}