-1
我试图循环遍历包含对象的列表。我正在使用天气API读取数据，并将每个数据成员存储为一个对象，然后将每个对象存储在一个列表中。在我存储整个列表后，我希望能够遍历列表并显示对象。我正在阅读Json的数据，我正在使用casablanca软件包来完成这项工作。我想要做的就是能够在我的main.cpp中的displayFullForcast函数中遍历我的列表。 这里是我的列表定义：在对象列表中循环
list<Weather> weather;
这里是我的头：
这是我实现：
#include "Weather.h"
#include <list>
#include <string>
#include <iostream>
using std::cout;
using std::endl;
using std::cin;
Weather::Weather(double currentTemperature, double maxTemperature, double minTemperature,
string weatherDescription, double humidity, string time) :
cityState(cityState), currentTemperature(currentTemperature), highTemperature(highTemperature), lowTemperature(lowTemperature),
weatherDescription(weatherDescription), humidity(humidity), time(time)
{
}
Weather::Weather()
{
cityState = "";
currentTemperature = 0.0;
highTemperature = 0.0;
lowTemperature = 0.0;
weatherDescription = "";
humidity = 0.0;
highestTemperature = 0.0;
lowestTemperature = 0.0;
}
Weather::~Weather()
{
}
这里是我的main.cpp
void displayFullForcast()
{
list<Weather>weather;
for (list<Weather>::iterator it = weather.begin(); it != weather.end(); ++it)
{
cout << *it << endl;
}
}
void displayTodayForcast()
{
list<Weather>weather;
}
void displayLowHigh()
{
list<Weather>weather;
}
void displayHumidity()
{
list<Weather>weather;
}
void displayMenu()
{
int choice = 0;
cout << "What option would you like to see:\n"
<< "(1) Forcast for 5 days\n"
<< "(2) Forcast for Today\n"
<< "(3) The Lowest and Highest Temperature\n"
<< "(4) Humidity for Today\n" << endl;
cin >> choice;
switch (choice)
{
case 1: displayFullForcast();
break;
case 2: displayTodayForcast();
break;
case 3: displayLowHigh();
break;
case 4: displayHumidity();
break;
}
}
void executeWeatherQuery()
{
http_client client(U("http://api.openweathermap.org"));
uri_builder builder(U("/data/2.5/forecast"));
builder.append_query(U("q"), U("Searcy,AR"));
builder.append_query(U("appid"), U("5ee41aef99a6e283abcdd5a04d89ae67"));
builder.append_query(U("units"), U("imperial"));
builder.append_query(U("mode"), U("json"));
http_response response = client.request(methods::GET, builder.to_string()).get();
web::json::value forecastJson = response.extract_json(true).get();
web::json::value forecastListJson = forecastJson.at(U("list"));
if (forecastListJson.is_array())
{
for (size_t i = 0; i < forecastListJson.size(); i++)
{
web::json::value forecastDayJson = forecastListJson[i];
web::json::value mainJson = forecastDayJson.at(U("main"));
web::json::value currentTemperatureJson = mainJson.at(U("temp"));
double currentTemperature = 0;
if (!currentTemperatureJson.is_null())
{
currentTemperature = currentTemperatureJson.as_double();
}
cout << "Current Temperature " << currentTemperature << endl;
web::json::value weatherJson = forecastDayJson.at(U("weather"))[0];
web::json::value mainWeatherJson = weatherJson.at(U("main"));
string weatherDescription = "";
if (!mainWeatherJson.is_null())
{
weatherDescription = conversions::to_utf8string(mainWeatherJson.as_string());
}
cout << "Weather Description " << conversions::to_utf8string(weatherDescription) << endl;
web::json::value MainJson = forecastDayJson.at(U("main"));
web::json::value minTemperatureJson = MainJson.at(U("temp"));
double minTemperature = 0;
if (!minTemperatureJson.is_null())
{
minTemperature = minTemperatureJson.as_double();
}
cout << "Min Temp: " << minTemperature << endl;
web::json::value MainMaxJson = forecastDayJson.at(U("main"));
web::json::value maxTemperatureJson = MainMaxJson.at(U("temp"));
double maxTemperature = 0;
if (!maxTemperatureJson.is_null())
{
maxTemperature = maxTemperatureJson.as_double();
}
cout << "Max " << maxTemperature << endl;
web::json::value MainHumidityJson = forecastDayJson.at(U("main"));
web::json::value humidityJson = MainHumidityJson.at(U("humidity"));
double humidity = 0;
if (!MainHumidityJson.is_null())
{
humidity = humidityJson.as_double();
}
cout << "Humidity: " << humidity << endl;
web::json::value MainTimeJson = forecastDayJson.at(U("dt_txt"));
string time = "";
if (!MainTimeJson.is_null())
{
time = conversions::to_utf8string(MainTimeJson.as_string());
//time = localtime(time);
}
cout << "Time" << time << endl;
Weather WeatherForcast(currentTemperature, maxTemperature, minTemperature,
weatherDescription, humidity, time);
list<Weather>weather;
weather.push_back(WeatherForcast);
}
}
}
void main()
{
/*string location;
cout << "Please enter a city and a State (Example: Searcy,AR)" << endl;
cin >> location;*/
executeWeatherQuery();
displayMenu();
}
**我是rec发出这个错误仍然在线上cout < < * it < < endl; 错误：没有运算符“< <”匹配这些操作数。操作数类型是std :: ofstream和Weather。
我也编辑了我的代码来修复范围错误。 –