Panoramio - 搜索一张图片API

Question

我有lat lng - 48.980861,16.523444。 如何从latLng whit API（JSON）搜索一张图片？

网址： http://www.panoramio.com/map/#lt=48.980842&ln=16.523444&z=-3&k=2&a=1&tab=1&pl=all

API： http://www.panoramio.com/map/get_panoramas.php?set=full&from=0&to=20&maxx=48.980861&maxy=16.523444&size=medium&mapfilter=true

URL = API 感谢

Answer 1

public class MapLocation 
{ 
    public double lat { get; set; } 
    public double lon { get; set; } 
    public int panoramio_zoom { get; set; } 
} 

public class Photo 
{ 
    public int height { get; set; } 
    public double latitude { get; set; } 
    public double longitude { get; set; } 
    public int owner_id { get; set; } 
    public string owner_name { get; set; } 
    public string owner_url { get; set; } 
    public string photo_file_url { get; set; } 
    public int photo_id { get; set; } 
    public string photo_title { get; set; } 
    public string photo_url { get; set; } 
    public string upload_date { get; set; } 
    public int width { get; set; } 
    public string place_id { get; set; } 
} 

public class RootObject 
{ 
    public int count { get; set; } 
    public bool has_more { get; set; } 
    public MapLocation map_location { get; set; } 
    public List<Photo> photos { get; set; } 
} 

var dataContractJsonSerializer = new DataContractJsonSerializer(typeof(RootObject)); 
RootObject readObject = (RootObject)dataContractJsonSerializer.ReadObject(memoryStream); 

foreach (var item in readObject.photos) 
{ 
    //item.photo_file_url 
    //item.photo_id 
    //item.photo_title 
    //item.photo_url 
    //item.upload_date 

    // and etc. 
} 

阅读这篇帖子Parsing JSON