问题，同时取出由数据库

机应用崩溃的第一个记录，当我试图选择数据库中的数据和他们没有记录问题，同时取出由数据库

错误：

"Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** +[NSString stringWithUTF8String:]: NULL cString'".

查询：arrList = [app.sk lookupAllForSQL:@"select * from tblFriendDetail"];

查找AllForSQL代码：

- (NSArray *)lookupAllForSQL:(NSString *)sql { 
     sqlite3_stmt *statement; 
     id result; 
     NSMutableArray *thisArray = [NSMutableArray arrayWithCapacity:4]; 
     if ((statement = [self prepare:sql])) { 
      while (sqlite3_step(statement) == SQLITE_ROW) { 
       NSMutableDictionary *thisDict = [NSMutableDictionary dictionaryWithCapacity:4]; 
       for (int i = 0 ; i < sqlite3_column_count(statement) ; i++) { 
        if (sqlite3_column_decltype(statement,i) != NULL && 
         strcasecmp(sqlite3_column_decltype(statement,i),"Boolean") == 0) { 
         result = [NSNumber numberWithBool:(BOOL)sqlite3_column_int(statement,i)]; 
        } else if (sqlite3_column_type(statement, i) == SQLITE_TEXT) { 
         result = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement,i)]; 
        } else if (sqlite3_column_type(statement,i) == SQLITE_INTEGER) { 
         result = [NSNumber numberWithInt:(int)sqlite3_column_int(statement,i)]; 
        } else if (sqlite3_column_type(statement,i) == SQLITE_FLOAT) { 
         result = [NSNumber numberWithFloat:(float)sqlite3_column_double(statement,i)];     
        } else { 
         result = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement,i)]; 
        } 
        if (result) { 
         [thisDict setObject:result 
            forKey:[NSString stringWithUTF8String:sqlite3_column_name(statement,i)]]; 
        } 
       } 
       [thisArray addObject:[NSDictionary dictionaryWithDictionary:thisDict]]; 
      } 
     } 
     sqlite3_finalize(statement); 
     return thisArray; 
    }

崩溃日志

#0 0x9599d176 in __kill() 
#1 0x9599d168 in kill$UNIX2003() 
#2 0x95a2f89d in raise() 
#3 0x95a459bc in abort() 
#4 0x93311fda in __gnu_cxx::__verbose_terminate_handler() 
#5 0x011a823b in _objc_terminate() 
#6 0x9331017a in __cxxabiv1::__terminate() 
#7 0x933101ba in std::terminate() 
#8 0x933102b8 in __cxa_throw() 
#9 0x011a8416 in objc_exception_throw() 
#10 0x0100cef8 in +[NSException raise:format:arguments:]() 
#11 0x0100ce6a in +[NSException raise:format:]() 
#12 0x00a06e35 in +[NSString stringWithUTF8String:]() 
#13 0x0000b6ab in -[SKDatabase lookupAllForSQL:] (self=0x59393e0, _cmd=0xf9ac, sql=0x13564) at SKDatabase.m:97 
#14 0x000052f9 in -[addGroupMembers viewWillAppear:] (self=0x4f2ce40, _cmd=0xe194, animated=1 '\001') at addGroupMembers.m:34 
#15 0x003649be in -[UINavigationController _startTransition:fromViewController:toViewController:]() 
#16 0x0035f32a in -[UINavigationController _startDeferredTransitionIfNeeded]() 
#17 0x00366562 in -[UINavigationController pushViewController:transition:forceImmediate:]() 
#18 0x0035f1c4 in -[UINavigationController pushViewController:animated:]() 
#19 0x00002d68 in -[GroupSelection editFriendListClicked:] (self=0x4f34da0, _cmd=0xdf58, sender=0x4f3a400) at GroupSelection.m:80 
#20 0x002a64fd in -[UIApplication sendAction:to:from:forEvent:]() 
#21 0x00336799 in -[UIControl sendAction:to:forEvent:]() 
#22 0x00338c2b in -[UIControl(Internal) _sendActionsForEvents:withEvent:]() 
#23 0x003377d8 in -[UIControl touchesEnded:withEvent:]() 
#24 0x002caded in -[UIWindow _sendTouchesForEvent:]() 
#25 0x002abc37 in -[UIApplication sendEvent:]() 
#26 0x002b0f2e in _UIApplicationHandleEvent() 
#27 0x012ff992 in PurpleEventCallback() 
#28 0x01035944 in __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE1_PERFORM_FUNCTION__() 
#29 0x00f95cf7 in __CFRunLoopDoSource1() 
#30 0x00f92f83 in __CFRunLoopRun() 
#31 0x00f92840 in CFRunLoopRunSpecific() 
#32 0x00f92761 in CFRunLoopRunInMode() 
#33 0x012fe1c4 in GSEventRunModal() 
#34 0x012fe289 in GSEventRun() 
#35 0x002b4c93 in UIApplicationMain() 
#36 0x00002199 in main (argc=1, argv=0xbffff084) at main.m:14

来源

2011-08-06 Baby Groot

请转到GDB并激活“BT”命令并编辑您的问题完整的崩溃日志。 – Tirth

你在方法中提到的返回类型是NSArray的，并且该方法返回的NSMutableArray！ –

@iApple Thnx为你的答案，但这没有帮助它仍然在同一地点崩溃。 –

我得到了解决方案。这是因为它从sqlite表中获得了空值。所以，现在当我输入数据时，我注意到我输入了所有字段的数据，虽然我没有输入字段，但输入的是空白字符串。

来源

2011-08-06 06:51:38

问题，同时取出由数据库

回答

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