2015-04-17 147 views
2

我想做一个查询,我得到一些ID,然后用逗号分开,并将其放在我的where子句中。WHERE子句与STUFF函数

但会出现以下错误

消息245,级别16,状态1,行转换nvarchar的值“2998,2999,3000,3001,3002,3003,3004当10
转换失败, 3005,3006,3007,3008,3009,3010,3011,3012,3013,3482,3483,3484,3485,3486,3487,3488,3489,3490,3491,3492,3493,3494,3495,...

我尝试了一些演员,但没有奏效。

样品查询:

SELECT A.ID, A.ID_PERIODO_GESTAO, A.ID_FILIAL, A.ID_RESPONSAVEL_AREA, A.ID_PARENT, A.ID_SOURCE, A.COD_AREA, A.DESC_AREA, A.ATIVO, A.USER_LOGIN_RESP, A.NOME_RESP, A.DESC_FILIAL, A.COD_AREA_SUP, A.FOTO_PATH, 
A.COLABORADOR_ID, 
CASE WHEN (SELECT COUNT(B.ID_COLABORADOR) FROM COLABORADOR_AREA B WHERE B.ID_AREA = A.ID GROUP BY B.ID_AREA) IS NULL THEN 0 ELSE 
(SELECT COUNT(B.ID_COLABORADOR) FROM COLABORADOR_AREA B WHERE B.ID_AREA = A.ID GROUP BY B.ID_AREA) END AS QTD_COLABORADORES, 
A.LEVEL_TREE,LEN(A.LEVEL_TREE), 

STUFF(
      (SELECT ',' + CAST(VW.ID AS VARCHAR(10)) 
      FROM VW_AREA VW 
      WHERE LEN(VW.LEVEL_TREE) > LEN(A.LEVEL_TREE) 
      AND VW.ID_PERIODO_GESTAO = 2     
      FOR XML PATH('')), 1, 1, '') 

FROM VW_AREA A 
LEFT JOIN dbo.COLABORADOR_AREA ON dbo.COLABORADOR_AREA.ID_COLABORADOR = A.COLABORADOR_ID   
WHERE A.ID_FILIAL IN (9) AND A.ID_PERIODO_GESTAO = 2 

UNION 

SELECT A.ID, A.ID_PERIODO_GESTAO, A.ID_FILIAL, A.ID_RESPONSAVEL_AREA, A.ID_PARENT, A.ID_SOURCE, A.COD_AREA, A.DESC_AREA, A.ATIVO, A.USER_LOGIN_RESP, A.NOME_RESP, A.DESC_FILIAL, A.COD_AREA_SUP, A.FOTO_PATH, 
A.COLABORADOR_ID, 
CASE WHEN (SELECT COUNT(B.ID_COLABORADOR) FROM COLABORADOR_AREA B WHERE B.ID_AREA = A.ID GROUP BY B.ID_AREA) IS NULL THEN 0 ELSE 
(SELECT COUNT(B.ID_COLABORADOR) FROM COLABORADOR_AREA B WHERE B.ID_AREA = A.ID GROUP BY B.ID_AREA) END AS QTD_COLABORADORES, 
A.LEVEL_TREE, LEN(A.LEVEL_TREE), 

    STUFF(
      (SELECT ',' + CAST(VW.ID AS VARCHAR(10)) 
      FROM VW_AREA VW 
      WHERE LEN(VW.LEVEL_TREE) > LEN(A.LEVEL_TREE) 
      AND VW.ID_PERIODO_GESTAO = 2   
      FOR XML PATH('')), 1, 1, '') AS 

FROM VW_AREA A 
LEFT JOIN dbo.COLABORADOR_AREA ON dbo.COLABORADOR_AREA.ID_COLABORADOR = A.COLABORADOR_ID 
JOIN CTE4 ON A.ID = CTE4.ID_PARENT 
WHERE A.ID_PERIODO_GESTAO = 2 
AND (A.ID IN (CTE4.ID_PARENT)) 

结果

QTD_COLABORATOR LEVEL_TREE  QTD_CARACTER_IN_LEVEL_TREE 
1     002   3 

最后一列,用那东西的功能,将含有这样的

2997,2998,2999,3000,3001,3002,3003,3004,3005,3006,3007,3008,3009,3010,3011,3012,3013,3014,3015,3016,3017

这是所有数据ID tha t在LEVEL_TREE中包含多于3个字符

+0

您能否向我们提供存储在您的VW_AREA视图中的ID的一些示例值? – FutbolFan

+0

您没有最后一列的别名。 –

回答

3

这绝不会起作用。你试图在一个字符串中使用一个比较器。因此,语法错误。有没有理由不能这样做?

SELECT SUM(A.ID) 
FROM COLABORATOR A 
WHERE A.ID IN (SELECT VW.ID FROM VW_AREA VW) 
+0

我更新了我的查询,现在我可以告诉你这不是那么简单。 Unfortunelly。 –

+0

与最初的问题相比,更新后的SQL并没有多大意义。它有一些明显不相关的语法错误,并没有显示你最初描述的问题。你能重新检查一下吗? – Necreaux

0

嗨STUFF会让你的价值观逗号分隔,并且IN子句将期待一个结果集的int,所以它崩溃, 你也许可以用动态字符串执行这样做:

SET @sqlCommand = 'SELECT ' + @columnList + ' FROM customers WHERE City = ' + @city 
EXEC (@sqlCommand)