参考当前日期获取一周中的日期数组

Question

有没有办法在一周内获取参考当前日期的日期数组？

Answer 1

能否请你去通过这个代码，

NSDate *startDate = ...; 
NSDate *endDate = ...; 
unsigned int unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit; 
NSDateComponents *comps = [gregorian components:unitFlags fromDate:startDate toDate:endDate options:0]; 
int months = [comps month]; 
int days = [comps day]; 

这是苹果公司一个简单的例子。 for more details

Answer 2

试试这个工作与我很好。 - （NSMutableArray的*）getWeekDays {

NSDate *today = [NSDate date]; 

    NSCalendar *gregorian = [[NSCalendar alloc] 

          initWithCalendarIdentifier:NSGregorianCalendar]; 

    NSDateComponents *weekdayComponents = 

    [gregorian components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:today]; 

    NSInteger day = [weekdayComponents day]; 

    NSInteger weekday = [weekdayComponents weekday]; 

    int i=(int)weekday; 
    int start,end; 
    if(i==7) 
    { 
     start=6; 
     end=0; 
    } 
    else if(i==6) 
    { 

     start=5; 
     end=1; 
    } 

    else if(i==5) 
    { 

     start=4; 
     end=2; 
    } 

    else if(i==4) 
    { 

     start=3; 
     end=3; 
    } 
    else if(i==3) 
    { 

     start=2; 
     end=4; 
    } 


    else if(i==2) 
    { 

     start=1; 
     end=5; 
    } 

    else if(i==1) 
    { 

     start=0; 
     end=6; 
    } 


    NSDate *cdate=[NSDate date]; 
    NSDateFormatter *df=[[NSDateFormatter alloc] init]; 
    [df setDateFormat:@"dd/MM/yyyy EEEE"]; 
    NSMutableArray *WeekDatesArr=[[NSMutableArray alloc] init]; 

    for(start;start>0;start--) 
    { 
     NSDate *FirstDate=[cdate addTimeInterval:-(86400)*start]; 
     NSString *str=[df stringFromDate:FirstDate]; 
     [WeekDatesArr addObject:str]; 
    } 
    for(int i=0;i<=end;i++) 
    { 
     NSDate *LastDate=[cdate addTimeInterval:(86400)*i]; 
     NSString *str1=[df stringFromDate:LastDate]; 
     NSLog(@"Str %@ ",str1); 
     [WeekDatesArr addObject:str1]; 
    } 
    NSLog(@"Dates Description in week %@",WeekDatesArr); 
    return WeekDatesArr; 
} 

干杯