排名查询结果聚合（计数）

我试图通过聚合函数获得排名值 - 我想看看它是否可以在MySQL查询（而不是ORM调用查询）内完成。排名查询结果聚合（计数）

表和数据我已经是这样的：

CREATE TABLE `interactions` (
    `id` bigint(20) NOT NULL AUTO_INCREMENT, 
    `account` varchar(100) COLLATE utf8_unicode_ci NOT NULL, 
    `timestamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, 
    PRIMARY KEY (`id`) 
) ENGINE=MyISAM; 

INSERT INTO `interactions` VALUES 
(1, "xyz", "2017-01-01 00:05:01"), 
(2, "xyz", "2017-01-01 00:05:10"), 
(3, "abc", "2017-01-01 00:05:21"), 
(4, "xyz", "2017-01-01 00:05:43"), 
(5, "def", "2017-01-01 00:05:47"), 
(6, "xyz", "2017-01-01 00:05:49"), 
(7, "abc", "2017-01-01 00:05:50"), 
(8, "abc", "2017-01-01 00:05:59");

到目前为止，我有：

set @curRank := 0; 

select 
    @curRank := @curRank + 1 AS rank, 
    der.account, 
    der.searches 
from 
    interactions 
right join 
    (select account, count(id) AS searches from interactions group by account order by searches) AS der 
on 
    der.account = interactions.account;

但这输出，在每个账户（用正确的searches值 - 但排名不止一次）：

1 abc  3 
2 abc  3 
3 abc  3 
4 def  1 
5 xyz  4 
6 xyz  4 
7 xyz  4 
8 xyz  4

我在寻找：

1 abc  3 
2 def  1 
3 xyz  4

我应该提及的是，我不在乎联合排名 - 如果两个账户在表格中以相同的计数结束，那么他们是否依次排列（或排列顺序）并不重要）。

来源

2017-02-02 HorusKol

见http://meta.stackoverflow.com/questions/333952/why-should-i-provide-an-mcve-for-what -seems-to-a-very-simple-sql-query – Strawberry

@Strawberry - 你能否指出你认为从这个问题中缺少的东西？只是一个数据集？ – HorusKol

链接的答案是不言自明的 – Strawberry

添加DISTINCT的SELECT修复查询：

set @curRank := 0; 

select distinct 
    der.account, 
    der.searches, 
    @curRank := @curRank + 1 AS rank 
from 
    interactions 
right join 
    (select account, count(id) AS searches from interactions group by account order by searches) AS der 
on 
    der.account = interactions.account;

来源

2017-02-02 22:35:19 HorusKol

排名查询结果聚合（计数）

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