分配高亮状态图像到Android图像按钮

Question

我跟其他地方的步骤，和我做了一个xml文件，像这样：

<selector xmlns:android="http://schemas.android.com/apk/res/android"> 

    <item android:drawable="@drawable/yeah2" 
     android:state_pressed="true" /> 
    <item android:drawable="@drawable/yeah" /> 

我为我的按钮活动的xml看起来是这样的：

<ImageButton 

    android:layout_width="150dp" 
    android:layout_height="wrap_content" 
    android:id="@+id/imageButton" 
    android:onClick="play1" 
    android:layout_below="@+id/textView" 
    android:layout_alignParentStart="true" 
    android:layout_marginTop="100dp" 
    android:src="@drawable/yeah" 
    android:clickable="false" 
    android:nestedScrollingEnabled="true" 
    android:background="@drawable/highlight" /> 

如何将突出显示的状态图像分配给Android图像按钮？这样

<?xml version="1.0" encoding="utf-8"?> 
<selector xmlns:android="http://schemas.android.com/apk/res/android"> 
<!-- Remember: order is important. First matching state(s) is rendered) --> 
<item 
    android:state_selected="true" 
    android:drawable="@drawable/yeah" /> 
<item 
    android:drawable="@drawable/yeah2" /> 

然后在Java中

Answer 1

使XML做以下

imageButton.setImageDrawable(getBaseContext().getResources().getDrawable(R.drawable.ImageButton)); 

//set the click listener 
imageButton.setOnClickListener(new OnClickListener() { 

public void onClick(View button) { 
    //Set the button's appearance 
    button.setSelected(!button.isSelected()); 

    if (button.isSelected()) { 
     //Handle selected state change 
    } else { 
     //Handle de-select state change 
    } 

} 

});