选择的记录不同的组，只有当所有记录某些列的有一定的价值

Question

我有8条记录下面的：

ID | Common ID | Reject 
------------------------- 
AB-1 | AB  | NULL 
AB-2 | AB  | YES 
AB-3 | AB  | NULL 
BB-1 | BB  | YES 
BB-2 | BB  | YES 
BB-3 | BB  | YES 
CB-1 | CB  | YES 
CB-2 | CB  | YES 
DB-1 | DB  | NULL 

我预期的结果是：

ID | Common ID | Reject 
------------------------- 
BB-1 | BB  | YES 
CB-1 | CB  | YES 

我只想当所有具有相同公共ID的记录的拒绝列为“是”时，获取不同的记录。

Answer 1

select min(ID), [Common ID], max(Reject) 
from tablename 
group by [Common ID] 
having count(*) = count(case when Reject = 'YES' then 1 end) 

如果[通用ID]具有相同的行数为YES的数量，然后回吧！

HAVING子句的count(*)返回[Common ID]的总行数。如果Reject = Yes，则case表达式返回1，否则返回null。右侧count返回大小写返回非空值的行数（即，当拒绝为是时！）当行数相同时，HAVING为真！

编辑：

在此特定情况下，当拒绝列值似乎是yes或NULL，则HAVING可以简化为：

having count(*) = count(Reject) 

然而，如果其它值（像NO）稍后会在列中找到，这是行不通的。所以我建议原始HAVING条款！

Answer 2

SELECT MIN(ID), CommonID, MIN(Reject) as Reject 
FROM yourtable 
GROUP BY CommonID 
HAVING MIN(ISNULL(Reject, '')) = MAX(ISNULL(Reject, '')) 
AND  MIN(ISNULL(Reject, '')) = 'Yes' 

编辑：你有NULL值，则需要使用ISNULL（）在列

Answer 3

在WHERE子句用GROUP BY一个子查询。

SELECT ID, [Common ID], Reject 
FROM yourtable 
WHERE (SELECT SUM(LEN(a.Reject)) 
     FROM yourtable a 
     WHERE ID = a.ID 
     GROUP BY a.ID) IS NULL 

输出：

SQL小提琴：

Answer 4

使用row_number窗口函数和not exists。有点复杂，但应该做的工作：

with cte as(select *, row_number(partition by commonid order by id) rn from table) 
select c.* 
from cte c 
where c.rn = 1 and 
     not exists(select * from table t 
       where t.commonid = c.commonid and 
         (t.reject is null or t.reject <> 'yes')) 

Answer 5

SELECT MIN(ID) as ID, [Common ID], MIN(Reject) as Reject 
FROM Table1 
GROUP BY [Common ID] 
HAVING MIN(ISNULL(Reject, '')) = 'YES' 

Answer 6

这将帮助你

select 
(select top 1 ID from YourTable where CommonID= t.CommonID and reject=t.reject)ID, 
CommonID, 
Reject 
from YourTable T 
group by 
CommonID,reject 
having (Reject is not null) 

Answer 7

试试这个

SELECT MIN(ID) AS ID, ColumnID, MIN(Reject) AS Reject 
     FROM tableName 
     WHERE Reject='YES' AND ID LIKE '%1' 
     GROUP BY ColumnID 

Answer 8

这是实现最简单的方法你预期结果。

SELECT ID, [Common ID], Reject 
FROM YOURTABLE 
WHERE REJECT = 'YES' 
GROUP BY ID, COMMON ID