我是新来的bash脚本。我想要逐行读取包含表格的文件。在每一行我都想把值赋给变量。这基本上是我的代码的格式:虽然循环错误:语法错误附近的意外令牌`完成'
#!/bin/bash
while IFS= read -r line; do
echo $a $b $c $d
#if statements…
done < test.txt
我得到这个错误:“虽然环错误:附近意外的标记语法错误'完成””
任何想法是错我的代码?我试着查看与同一个错误有关的其他几个问题,但我无法修复我的代码。感谢您的帮助!
编辑:这是整个代码。它可能有其他错误(我真的是一个初学者),但我希望它有帮助。
#!/bin/bash
experiment_database="/home/gperron/datasets/ENCODE_tables/final_tables/test_experiment_database.txt"
file_database="/home/gperron/datasets/ENCODE_tables/final_tables/test_file_database.txt"
EXPERIMENT=`cat $experiment_database | head -n $PBS_ARRAYID | tail -n 1 | cut -f1`
echo "EXPERIMENT #$PBS_ARRAYID: $EXPERIMENT"
while IFS= read -r line; do
echo $file_ID $experiment $target $biological_replicate $technical_replicate $read_number $url $fastq_file $genome
if [ "$experiment" == "$EXPERIMENT" ]; then
if [ $biological_replicate == 1 ]; then
if [ $technical_replicate == 1 ]; then
if [ $read_number == 1 ]; then
ID_111= $file_ID
fastq_111= $fastq_file
url_111= $url
echo "FASTQ file 111 ID: $ID_111"
echo "FASTQ file 111: $fastq_111"
echo "FASTQ file 111 url: $url_111"
elif [ $read_number == 2 ]; then
ID_112= $file_ID
fastq_112= $fastq_file
url_112= $url
echo "FASTQ file 112 ID: $ID_112"
echo "FASTQ file 112: $fastq_112"
echo "FASTQ file 112 url: $url_112"
fi
elif [ $technical_replicate == 2 ]; then
if [ $read_number == 1 ]; then
ID_121= $file_ID
fastq_121= $fastq_file
url_121= $url
echo "FASTQ file 121 ID: $ID_121"
echo "FASTQ file 121: $fastq_121"
echo "FASTQ file 121 url: $url_121"
elif [ $read_number == 2 ]; then
ID_122= $file_ID
fastq_122= $fastq_file
url_122= $url
echo "FASTQ file 122 ID: $ID_122"
echo "FASTQ file 122: $fastq_122"
echo "FASTQ file 122 url: $url_122"
fi
elif [ $biological_replicate == 2 ]; then
if [ $technical_replicate == 1 ]; then
if [ $read_number == 1 ]; then
ID_211= $file_ID
fastq_211= $fastq_file
url_211= $url
echo "FASTQ file 211 ID: $ID_211"
echo "FASTQ file 211: $fastq_211"
echo "FASTQ file 211 url: $url_211"
elif [ $read_number == 2 ]; then
ID_212= $file_ID
fastq_212= $fastq_file
url_212= $url
echo "FASTQ file 212 ID: $ID_212"
echo "FASTQ file 212: $fastq_212"
echo "FASTQ file 212 url: $url_212"
fi
elif [ $technical_replicate == 2 ]; then
if [ $read_number == 1 ]; then
ID_221= $file_ID
fastq_221= $fastq_file
url_221= $url
echo "FASTQ file 221 ID: $ID_221"
echo "FASTQ file 221: $fastq_221"
echo "FASTQ file 221 url: $url_221"
elif [ $read_number == 2 ]; then
ID_222= $file_ID
fastq_222= $fastq_file
url_222= $url
echo "FASTQ file 222 ID: $ID_222"
echo "FASTQ file 222: $fastq_222"
echo "FASTQ file 222 url: $url_222"
fi
fi
fi
fi
done < test_file_database.txt
请让我知道,如果我得到任何澄清。
后循环的肉。你可能有一些未封闭的嵌套构造或不平衡的parens或东西。 –
我在您发布的代码中看不到任何错误。创建一个再现问题的最小示例,并将* exact *代码复制并粘贴到您的问题中。 (您可能会在缩小测试用例的同时自己解决问题;在这种情况下,您可以删除问题或发布答案,具体取决于其他用户是否有用。) –
您发布的代码显然适用于-is –