2011-06-23 63 views
2

我有一个基类,并且在其中放置了一个抽象函数。现在我从它继承并在派生类中声明了该函数。但Visual Studio仍然不会编译我的代码,并坚持派生类是抽象的。我甚至复制并粘贴了基类中的声明,并删除了virtual=0,但仍然出现错误。我已经明确限定了全局范围内的所有参数和返回值。有什么建议么?无法覆盖抽象函数CreateFont

#include "OS/Windows/Windows.h" 

#ifdef _DEBUG 
#define D3D_DEBUG_INFO 
#define D3DCALL(a) Wide::Render::CheckResult(a, #a) 
#else 
#define D3DCALL(a) a 
#endif 
#define D3DXFX_LARGEADDRESS_HANDLE 

extern "C" { 
    Wide::Render::Render* CreateRender(Wide::OSystem::Windows::WindowsOS* ptr); 
} 

namespace Wide { 
    namespace Render { 
     class D3D9Render : public Wide::Render::Render { 
      friend Render* ::CreateRender(Wide::OSystem::Windows::WindowsOS*); 
      D3D9Render(Wide::OSystem::Windows::WindowsOS* os); 

      Wide::Colour ScreenBackground; 

     public: 
      Wide::Colour GetScreenBackground(); 
      Render* SetScreenBackground(Wide::Colour); 
      void RenderFrame(); 

      int GetFramesPerSecond(); 
      std::shared_ptr<Wide::Render::Font> GetDefaultFont(); 
      std::shared_ptr<Wide::Render::Font> CreateFont(
       string name, 
       int weight, 
       int width, 
       int height, 
       bool italic 
      ); 
     }; 
    } 
} 

Windows头包括渲染头,相关的摘录这是贴在下面:

namespace Wide { 
    namespace Render { 
     struct Font; 
     struct Label { 
      virtual ::Wide::string Text() = 0; 
      virtual Label* Text(::Wide::string) = 0; 

      virtual std::shared_ptr<::Wide::Render::Font> Font() = 0; 
      virtual Label* Font(std::shared_ptr<::Wide::Render::Font>) = 0; 

      virtual Label* Position(::Wide::Rectangle) = 0; 
      virtual ::Wide::Rectangle Position() = 0; 

      virtual ::Wide::Colour Colour() = 0; 
      virtual Label* Colour(::Wide::Colour) = 0; 

      virtual ~Label() {} 
     }; 
     struct Font { 
      virtual ::Wide::string Name() const = 0; 
      virtual bool Italic() const = 0; 
      virtual int Weight() const = 0; 
      virtual int Width() const = 0; 
      virtual int Height() const = 0; 
      virtual std::unique_ptr<::Wide::Render::Label> CreateLabel() = 0; 

      virtual ~Font() {} 
     }; 
     struct Texture; 
     struct Sprite {   
      virtual std::shared_ptr<::Wide::Render::Texture> Texture() = 0; 
      virtual Sprite* Texture(std::shared_ptr<::Wide::Render::Texture>) = 0; 

      virtual Sprite* Position(::Wide::Rectangle) = 0; 
      virtual ::Wide::Rectangle Position() = 0; 

      virtual ::Wide::Colour Colour() = 0; 
      virtual Sprite* Colour(::Wide::Colour) = 0; 

      virtual float Depth() = 0; 
      virtual Sprite* Depth(float) = 0; 

      virtual ~Sprite() {} 
     }; 
     struct Texture { 
      virtual ::Wide::Point Size() = 0; 
      virtual ::Wide::string Filepath() = 0; 

      virtual std::unique_ptr<Sprite> CreateSprite() = 0; 
      virtual ~Texture() {} 
     }; 
     struct Render { 
      virtual ::Wide::Colour GetScreenBackground() = 0; 
      virtual Render* SetScreenBackground(::Wide::Colour) = 0; 
      virtual void RenderFrame() = 0; 
      virtual int GetFramesPerSecond() = 0; 

      virtual std::shared_ptr<Wide::Render::Font> GetDefaultFont() = 0; 
      virtual std::shared_ptr<Wide::Render::Font> CreateFont(
       string name, 
       int weight, 
       int width, 
       int height, 
       bool italic 
      ) = 0; 

      virtual ~Render() {} 
     }; 
    } 
} 

编辑:该错误是非常明确的。

d:\backups\code\projects\ngin4\d3d9render\d3d9render.cpp(9): error C2259: 'Wide::Render::D3D9Render' : cannot instantiate abstract class 
      due to following members: 
      'std::tr1::shared_ptr<_Ty> Wide::Render::Render::CreateFont(Wide::string,int,int,int,bool)' : is abstract 
      with 
      [ 
       _Ty=Wide::Render::Font 
      ] 
      d:\backups\code\projects\ngin4\ngin4\render.h(107) : see declaration of 'Wide::Render::Render::CreateFont' 
+2

请张贴代码示例演示问题 –

+0

也许你有一些预编译的头,你点击构建,而不是重建? –

+0

@Armen:我绝对没有任何预编译头文件。 – Puppy

回答

3

的WINDOWS.H定义的CreateFont为CreateFontW(和许多其他标识符以类似的方式),导致许多令人惊讶的编译错误一些包含单:

#define CreateFont CreateFontW 

的常见解决方法(假设你不需要调用这个GDI函数)就是在包含windows.h之后取消定义符号,或者避免完全使用这些Win32 API的名称。

#undef CreateFont