加入多个变量表并输出所有列名和数据类型到一个变量

Question

我有很多变量表和每个表都有这么多列在里面。我想知道每个变量表的所有列名和数据类型，而无需通过每个变量表来标识它们是手动的。我试过使用sys.columns，但当然它不起作用，因为变量表信息没有存储在系统数据库中。

所有列名的结果应该像@AllColumnsAndDataTypes的结果。请参阅代码中的推荐内容。谢谢

  ALTER proc [dbo].[usp_BigCodes] 
      as 
      begin 

      --Multiple table variables 
      declare @Table_01 table(TB01_MasterID int, Column_01 nvarchar(100), Column_02 nvarchar(100)) 
      declare @Table_02 table(TB02_MasterID int, Column_03 nvarchar(100), Column_04 nvarchar(100)) 
      declare @Table_03 table(TB03_MasterID int, Column_04 nvarchar(100), Column_05 nvarchar(100)) 

       ---I need to convert all of the code above programatically into 1 table 
      --The result should be out put into the @AllColumnsAndDataTypes 
      declare @AllColumnsAndDataTypes nvarchar(max) 
      --Result should be similar to below. 
      set @AllColumnsAndDataTypes=' 
             TB01_MasterID int, Column_01 nvarchar(100), Column_02 nvarchar(100) 
             TB02_MasterID int, Column_03 nvarchar(100), Column_04 nvarchar(100) 
             TB03_MasterID int, Column_04 nvarchar(100), Column_05 nvarchar(100) 
             ' 
      ---Need code to do output the result into the variable like on line 15 to 17 
       --Join all table variables and output all columns names and datatype into @AllColumnsAndDataTypes 
       select @AllColumnsAndDataTypes = ???????? from 
       @Table_01 as T1 
       INNER JOIN @Table_02 as T2 ON T1.TB01_MasterID=T2.TB02_MasterID 
       INNER JOIN @Table_03 as T3 ON T1.TB01_MasterID=T3.TB03_MasterID 

      --Display the result 
      select @AllColumnsAndDataTypes as AllColumnsInfo 
      end 

Answer 1

您可以使用sys.columns，但你必须这样做，在TempDB

Source

例的情况下：

declare @foo table (bar int, blah varchar(30)) 
declare @object_name sysname, @object_id int 

select @object_name = OBJECT_NAME([object_id], DB_ID('TempDB')) 
     ,@object_id = [object_id] 
from  tempdb.sys.columns 
where name = 'bar' 

select @object_name [object_name], @object_id [object_id] 

select [object_id], name 
from  tempdb.sys.columns 
where [object_id] = @object_id 

Answer 2

请尝试以下...

declare @Table_01 table(TB01_MasterID int, Column_01 nvarchar(100), Column_02 nvarchar(100)) 

select TN.N.value('local-name(.)', 'sysname') as ColumnName 
from 
    (
    select TV.* 
    from (select 1) as D(N) 
    outer apply (
       select top(0) * 
       from @Table_01 
       ) as TV 
    for xml path(''), elements xsinil, type 
) as TX(X) 
cross apply TX.X.nodes('*') as TN(N)