使用PHP while循环创建高级筛选器

Question

我有一个问题，那就是我想在网站上创建一个链接，就像人们可以单击链接来显示某些产品仅依赖于百分比。例如，我在我的数据库中有折扣百分比的列，它会显示最小折扣和最大折扣。假设我们有最低和最高折扣。 $ min = 12和$ max = 94;并且我想将它们放入链接中，以仅显示具有某些折扣的产品，例如过滤。下面是链接的例子。

<a href="#">12% to 20%</a 
    <a href="#">21% to 30%</a> 
    <a href="#">31% to 40%</a> and so on until it reaches 
    <a href="#">81% to 90%</a> and the last will be 
    <a href="#">91% to 94%</a> 

最小和最大的数字将来自数据库中的一列，它们可以频繁更改。我想出了解决方案，它的工作正常，但我的代码太长，就像我采取了很多步骤，可以在几行代码中完成。我在下面粘贴了我的工作代码，但我相信这可以减少为几行代码。

$catsql25 = "SELECT MAX(down_percentage) as largest FROM hot_deals"; 
$catquery25 = mysqli_query($conn, $catsql25); 
while ($row25 = mysqli_fetch_array($catquery25, MYSQLI_ASSOC)){ 
    $largest_number = $row25['largest']; 
} 

$catsql26 = "SELECT MIN(down_percentage) as smallest FROM hot_deals"; 
$catquery26 = mysqli_query($conn, $catsql26); 
while ($row26 = mysqli_fetch_array($catquery26, MYSQLI_ASSOC)){ 
    $smallest_number = $row26['smallest']; 
} 

$array_tens = array(10,20,30,40,50,60,70,80,90,100); 


foreach ($array_tens as $value){ 

    if(($value - $smallest_number <= 10) && ($value - $smallest_number > 0)){ 
     echo '<a href="/exp.php?fst='.$smallest_number.'&lst='.$value.'"><div class="lfmen2">'; 
     echo $smallest_number." to ".$value."</div></a>"; 
     $next_num = $value + 1; 
     $next_ten = 9; 
     $stop_num = floor($largest_number/10); 
     $stop_num2 = $stop_num * 10; 
     //echo $stop_num2.'<br>'; 
     $num_rounds = $stop_num2 - $value; 
     $num_rounds2 = $num_rounds/10; 
     //echo $num_rounds2; 
     for ($i = 1; $i <= $num_rounds2; $i++){ 
     $end_num = $next_num + $next_ten; 
     echo '<a href="/exp.php?fst='.$next_num.'&lst='.$end_num.'"><div class="lfmen2">'; 
     echo $next_num; 
     echo " to "; 
     echo $end_num; 
     echo "</div></a>"; 
     $next_num += 10; 
     $end_num += 10; 
     } 
    } 
} 


foreach ($array_tens as $value2){ 

    if(($largest_number - $value2 < 10) && ($largest_number - $value2 > 0)){ 
     $lsst = $value2 + 1; 
     if($lsst != $largest_number){ 
     echo '<a href="/exp.php?fst='.$lsst.'&lst='.$largest_number.'"><div class="lfmen2">'.$lsst." to ".$largest_number."</div></a>"; 
     } 
     elseif($lsst == $largest_number){ 
      echo '<a href="/exp.php?fnly='.$largest_number.'"><div class="lfmen2">'.$largest_number.'</div></a>'; 
     } 
    } 

} 

我知道它的所有烂摊子，但.. 谢谢。

Answer 1

你可以做的第一件事情就是只有一个SQL查询：

$catsql = "SELECT MAX(down_percentage) as largest, MIN(down_percentage) as smallest FROM hot_deals"; 

然后你只需要一个循环：

$catquery = mysqli_query($conn, $catsql); 
while ($row = mysqli_fetch_array($catquery, MYSQLI_ASSOC)){ 
    $largest_number = $row['largest']; 
    $smallest_number = $row['smalest']; 
} 

之后，你可以做只有一个foreach循环。这两个“如果”条件可能是在同一个循环：

foreach ($array_tens as $value) { 

    if (($value - $smallest_number <= 10) && ($value - $smallest_number > 0)) { 
     echo '<a href="/exp.php?fst='.$smallest_number.'&lst='.$value.'"><div class="lfmen2">'; 
     echo $smallest_number." to ".$value."</div></a>"; 
     $next_num = $value + 1; 
     $next_ten = 9; 
     $stop_num = floor($largest_number/10); 
     $stop_num2 = $stop_num * 10; 
     //echo $stop_num2.'<br>'; 
     $num_rounds = $stop_num2 - $value; 
     $num_rounds2 = $num_rounds/10; 
     //echo $num_rounds2; 
     for ($i = 1; $i <= $num_rounds2; $i++) { 
      $end_num = $next_num + $next_ten; 
      echo '<a href="/exp.php?fst='.$next_num.'&lst='.$end_num.'"><div class="lfmen2">'; 
      echo $next_num; 
      echo " to "; 
      echo $end_num; 
      echo "</div></a>"; 
      $next_num += 10; 
      $end_num += 10; 
     } 
    } 

    if (($largest_number - $value < 10) && ($largest_number - $value > 0)) { 
     $lsst = $value + 1; 
     if ($lsst != $largest_number) { 
      echo '<a href="/exp.php?fst='.$lsst.'&lst='.$largest_number.'"><div class="lfmen2">'.$lsst." to ".$largest_number."</div></a>"; 
     } elseif ($lsst == $largest_number) { 
      echo '<a href="/exp.php?fnly='.$largest_number.'"><div class="lfmen2">'.$largest_number.'</div></a>'; 
     } 
    } 
} 

为了使其更具可读性，你也可以评论你的代码知道什么做什么。

这是一个很好的缩进，你是对的。

希望它有帮助。