计算python中两个日期之间的9:00 PM

Question

如何计算两个日期之间9:00 PM可以进行多少次？

dt_start_time = "2014-09-23 11:00:00" 
dt_end_time = "2014-09-24 12:00:00" 

预期成果是1

dt_start_time = "2014-09-24 09:00:00" 
dt_end_time = "2014-09-24 22:00:00" 

预期输出1

dt_start_time = "2014-09-24 09:00:00" 
dt_end_time = "2014-09-26 12:00:00" 

预期产出2

Answer 1

你可以简单地通过转换为两个日期之间的时间差做天，并且如果日期范围由于四舍五入而错过额外的晚上9点，则增加额外的一天

dt_start_time = "2014-09-23 11:00:00" 
dt_end_time = "2014-09-24 23:00:00" 

format = "%Y-%m-%d %H:%M:%S" 

from datetime import datetime as dt 

st = dt.strptime(dt_start_time, format) 
end = dt.strptime(dt_end_time, format) 

count = (end - st).days 
if st.hour < 21 and end.hour >= 21: 
    count += 1 
print count