我有一个EmailService EJB,它有一个非常简单的'send_email'方法。尽管显然有一个不带参数的公共构造函数,但我仍然接受了标题中的错误。以下是确切的错误和类代码。这很混乱。'Bean没有一个没有参数错误的公共构造函数',尽管显然有一个错误?
错误:
[ERROR ] CNTR5007E: The websphere.jaxrs.service.EmailService bean class for the WebApiConsole#WebApiConsole.war#EmailService bean does not have a public constructor that does not take parameters.
在这里看到错误的详细信息(不多见):http://pic.dhe.ibm.com/infocenter/wxdinfo/v6r1/index.jsp?topic=%2Fcom.ibm.websphere.messages.doc%2Fcom.ibm.ejs.container.container.html
代码:
package websphere.jaxrs.service;
import javax.ejb.EJB;
import javax.ejb.LocalBean;
import javax.ejb.Stateless;
import org.apache.commons.mail.Email;
import org.apache.commons.mail.EmailException;
import org.apache.commons.mail.SimpleEmail;
import websphere.jaxrs.helpers.ContextFinder;
/**
* This class provides an interface for emailing messages. It uses server environment variables to configure SMTP server and port and authentication.
*
* @author me
*
*/
@Stateless
@LocalBean
public class EmailService {
@EJB ContextFinder ctf;
private static final String EMAIL_PASSWORD_JNDI_NAME = "EMAIL_PASSWORD";
private static final String EMAIL_USERNAME_JNDI_NAME = "EMAIL_USERNAME";
private static final String SMTP_SERVER_JNDI_NAME = "SMTP_SERVER";
private static final String SMTP_PORT_JNDI_NAME = "SMTP_PORT";
private String username;
private String password;
private String server;
private Integer port;
public EmailService() {
username = (String) ctf.lookup(EMAIL_USERNAME_JNDI_NAME);
password = (String) ctf.lookup(EMAIL_PASSWORD_JNDI_NAME);
server = (String) ctf.lookup(SMTP_SERVER_JNDI_NAME);
port = (Integer) ctf.lookup(SMTP_PORT_JNDI_NAME);
}
/**
* Sends an email to a specific user.
*
* @param sendTo
* @param subject
* @param message
*/
public void sendMail(String sendTo, String subject, String message) {
try {
Email email = new SimpleEmail();
email.setHostName(server);
email.setSmtpPort(port);
email.setAuthentication(username, password);
email.setSSLOnConnect(true);
email.setFrom(username);
email.setSubject(subject);
email.setMsg(message);
email.addTo(sendTo);
email.send();
} catch (EmailException e) {
System.err.println("Failed to email");
e.printStackTrace();
}
}
}
我倾向于认为这是一个错误。我可能是错的,但是在上面的类中,一切都非常独立(没有其他配置,我知道它是必需的),并且我不断收到此错误。我尝试重建项目。
[编辑]我做了一些实验,非常具体,删除sendMail()导致它没有错误。
因为我从来不知道它。 [编辑] Woops,太快击中'输入'。它的工作!我可以问为什么? – user2316667