C++ strptime忽略解析时区

Question

当我运行下面的代码strptime似乎忽略了时区值。只需设置当地时区的值（即+10）。

这是输出，（在Linux上运行，用gcc 4.6.3编译）：

-----------2013-04-24T9:47:06+400 - %Y-%m-%dT%H:%M:%S%z 
TM Break H:9 is DST:0 GMT Off:0 
The epoch value: 1366760826 
DateTime in String:  04/24/13 - 09:47AM +1000 

-----------2013-04-24T11:47:06+800 - %Y-%m-%dT%H:%M:%S%z 
TM Break H:11 is DST:0 GMT Off:36000 
The epoch value: 1366768026 
DateTime in String:  04/24/13 - 11:47AM +1000 

-----------2013-04-24T9:47:06+0 - %Y-%m-%dT%H:%M:%S%z 
TM Break H:9 is DST:0 GMT Off:36000 
The epoch value: 1366760826 
DateTime in String:  04/24/13 - 09:47AM +1000 

-----------2013-04-24T9:47:06+4 - %Y-%m-%dT%H:%M:%S%z 
TM Break H:9 is DST:0 GMT Off:36000 
The epoch value: 1366760826 
DateTime in String:  04/24/13 - 09:47AM +1000 

这是代码：

void date_Test(){ 
    string dateStrings[] = {"2013-04-24T9:47:06+400" 
          , "2013-04-24T11:47:06+800" 
          , "2013-04-24T9:47:06+0" 
          , "2013-04-24T9:47:06+4"}; 
    string formatStrings[] = {"%Y-%m-%dT%H:%M:%S%z" 
          , "%Y-%m-%dT%H:%M:%S%z" 
          , "%Y-%m-%dT%H:%M:%S%z" 
          , "%Y-%m-%dT%H:%M:%S%z"}; 

process_Timezone(dateStrings, formatStrings); 
} 

void process_Timezone(string dateStrings[], string formatStrings[]){ 
    int num = 4; 

    for (int i = 0; i < num; i++) { 
     cout << endl << "-----------" << dateStrings[i] << " - " << formatStrings[i] << endl; 
     tm *dtm = new tm; 
     strptime(dateStrings[i].c_str(), formatStrings[i].c_str(), dtm); 
     cout << "TM Break \tH:" << dtm->tm_hour << " is DST:" << dtm->tm_isdst << " GMT Off:" << dtm->tm_gmtoff << endl; 
     time_t ep_dt = mktime(dtm); 
     cout << "The epoch value: \t" << ep_dt << endl; 
     char buffer[40]; 
     strftime(buffer, 40,"%x - %I:%M%p %z", dtm); 
     cout << "DateTime in String: \t" << buffer << endl; 
     delete dtm; 
    } 
} 

Answer 1

根据http://en.wikipedia.org/wiki/ISO_8601你一和三数字时区偏移量不是有效的ISO 8601值（至少在Linux上使用的格式为strptime），这需要hh[:][mm]作为格式。