如何通过字母

Question

订购的MySQL行，我有：

---------------------------- 
| ID   | Workout  | 
|_____________|______________| 
| 1   |What Chest | 
| 2   |Me self it's | 
| 3   |End workout | 
_____________________________ 

基本上我有一个like查询是：

SELECT * FROM db.table WHERE wourkout LIKE '%e%' 

现在我需要根据信e首先在命令行中发现行。 准确地说应该责令其想：

---------------------------- 
| ID   | Workout  | 
|_____________|______________| 
| 1   |End Workout | 
| 2   |Me self it's | 
| 3   |What Chest | 
_____________________________ 

正如你可以看到我的End workout行包含字母e之前其他行做。

Answer 1

SELECT * FROM db.table 
WHERE workout LIKE '%e%' 
ORDER BY INSTR(workout, _utf8'e') ASC 

只要workout不是二进制串，INSTR将返回第一"e"（或E）在workout的位置; 1为开头，2为第二位...