PHP重定向到不同的页面表格后提交

这里是我的表单代码PHP重定向到不同的页面表格后提交

<form action="PHP/form.php" id="msform" method="post"> 

<fieldset id="owner_service"> 
<h2> ARE YOU A DOG OWNER OR SERVICE PROVIDER?</h2> 
<legend>owner_service</legend> 
<div class="owner_service"> 
<input type="radio" id="service" name="owner_service" value="service"> 
<label for ="service"><h5>SERVICE PROVIDER</h5></label> 
<input type="radio" id="owner" name="owner_service" value="owner"> 
<label for ="owner"><h5>DOG OWNER</h5></label> 
</div> 
<input type="button" name="next" class="next action-button" id="next" value="NEXT" /> 
</fieldset>

第一位和这里的PHP

<?php 
session_start(); 

$servername = ""; 
$username = ""; 
$password = ""; 
$dbname = ""; 

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 


$sql = "INSERT INTO pets (owner_service, Gender, Age, Size, Location, idealLocation, Service) 
VALUES ('{$_POST['owner_service']}', '{$_POST['gender']}', '{$_POST['age']}', '{$_POST['size']}', '$locationCommaString', '{$_POST['ideal_location']}', '{$_POST['service']}')"; 



if($conn->query($sql) === TRUE) { 
    echo "New record created successfully"; 
} else { 
    echo "Error: " . $sql . "<br>" . $conn->error; 
} 


?>

我有我的形式运行，所以结果是数据库，但是我想要做的是根据用户点击“服务提供商”还是“狗主人”，将用户带到新的页面。我不知道在哪里放置标题，因为如果我替换已有的if语句，那么结果将不会显示在我的数据库中。

来源

2015-05-12 laimingl

if(isset($_POST['next'])) { 

    // your code to save data 
    // after submit without db error 

    if($_POST['owner_service'] == 'service') { // redirect page; } 
    else if($_POST['owner_service'] == 'owner') { // redirect page; } 

}

把它放在同一个回声的范围“新记录创建成功”;

来源

2015-05-12 10:13:39

if语句的查询执行后进入。什么@laimingl建议

来源

2015-05-12 10:16:43

<?php 
session_start(); 

$servername = ""; 
$username = ""; 
$password = ""; 
$dbname = ""; 

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 


$sql = "INSERT INTO pets (owner_service, Gender, Age, Size, Location, idealLocation, Service) 
VALUES ('{$_POST['owner_service']}', '{$_POST['gender']}', '{$_POST['age']}', '{$_POST['size']}', '$locationCommaString', '{$_POST['ideal_location']}', '{$_POST['service']}')"; 



if($conn->query($sql) === TRUE) { 
    echo "New record created successfully"; 
    $serv = $_POST['owner_service'] ; 
    switch($serv){ 
    case 'case 1': 
      // Page redirection code here 
    break; 

    case 'case 2': 
    // Page redirection code here 
    break; 





} else { 
    echo "Error: " . $sql . "<br>" . $conn->error; 
} 


?>

来源

2015-05-12 11:21:43

嘿此感谢，但是当我尝试这个代码，它只是带我到“回声;页面，如果我尝试删除该代码，它会将我带到一个空白页面。我会告诉你我的代码 if（$ conn-> query（$ sql）=== TRUE）{ $ serv = $ _POST ['owner_service']; 开关（$ SERV）{ 壳体 '壳体1'：头（ '位置：service_form.html'）; \t \t exit; 休息; 情况下 '壳体2'： \t \t头（ '位置：owner_form.html'）; \t \t exit; 休息; } } else { echo“Error：”。 $ sql。 “
”。 $ conn->的错误; } – laimingl

您的问题是否已解决？ –

我设法使用javascript document.location来解决它 – laimingl

-1

类似只需更改input type="button"到input type="submit"。

来源

2017-04-16 23:35:10 Edouard

PHP重定向到不同的页面表格后提交

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