2014-01-30 37 views
2

我是新来的php和google api,我试图在用户使用Google+进行登录时获取电子邮件地址,使用用户信息$加功能>以人为>获取(“我”),但是当我试图把它失败,此错误的电子邮件地址:当用户使用Google Oauth2和people.me进行身份验证时如何获取电子邮件地址

PHP公告:未定义指数:值

这里是我的代码:

<?php 
session_start(); 

set_include_path(get_include_path() . PATH_SEPARATOR . $_SERVER['DOCUMENT_ROOT'] . "/src"); 

require_once 'Google/Client.php'; 

require_once 'Google/Service/Plus.php'; 

$client_id = 'XXXXXXXXXXXXXXXXXXXX.apps.googleusercontent.com'; 
$client_secret = 'XXXXXXXXXXXXXXXXXXX'; 
$redirect_uri = 'http://www.XXXXXXXXXXXXXX.com/pruebas.php'; 

$client = new Google_Client(); 
$client->setClientId($client_id); 
$client->setClientSecret($client_secret); 
$client->setRedirectUri($redirect_uri); 
$client->addScope("https://www.googleapis.com/auth/userinfo.profile"); 
$client->addScope("https://www.googleapis.com/auth/userinfo.email"); 

$plus = new Google_Service_Plus($client); 

if (isset($_REQUEST['logout'])) { 
    unset($_SESSION['access_token']); 
} 

if (isset($_GET['code'])) { 
    $client->authenticate($_GET['code']); 
    $_SESSION['access_token'] = $client->getAccessToken(); 
    $redirect = 'http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF']; 
    header('Location: ' . filter_var($redirect, FILTER_SANITIZE_URL)); 

} 

if (isset($_SESSION['access_token']) && $_SESSION['access_token']) { 
    $client->setAccessToken($_SESSION['access_token']); 
    $_SESSION['token'] = $client->getAccessToken(); 

} else { 
    $authUrl = $client->createAuthUrl(); 
} 
?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head><title>Pruebas</title></head> 
<body> 
<?php if (isset($authUrl)) { 
    print "<a class='login' href='$authUrl'><img src='logogoo/Red-signin-Medium-base-32dp.png'></a>"; 
} else { 
    print "<a class='logout' href='pruebas.php?logout'>Cerrar:</a>"; 
} 

if (isset($_SESSION['access_token'])) { 
    $me = $plus->people->get("me"); 

    print "<br>ID: {$me['id']}\n<br>"; 
    print "Display Name: {$me['displayName']}\n<br>"; 
    print "Image Url: {$me['image']['url']}\n<br>"; 
    print "Url: {$me['url']}\n<br>"; 
    $name3 = $me['name']['givenName']; 
    echo "Nombre: $name3 <br>"; //Everything works fine until I try to get the email 
    $correo = ($me['emails']['value']); 
    echo $correo; 
    } 
?> 
</body> 
</html> 

我只是要从$ me获取帐户电子邮件地址以将其存储在我的应用程序中。

谢谢。

回答

6

$ me ['emails']是一个数组,而不是散列。所以添加[0]用于选择第一有电子邮件地址:

$correo = ($me['emails'][0]['value']); 

现在应该正常工作...

相关问题