将byte []数组转换为字节数

Question

我有一个偶数的长度的byte []数组。 现在，我希望byte []数组的前半部分的长度与byte []数组中的前两个字节一起作为字节b1，后两个字节b2等等。

请帮忙。 谢谢

Answer 1

这功课吗？我想你的主要问题是将成对的字节组合成双字节。这是通过什么叫做左移（<<）实现的，该字节为8位，所以由8个移动：

int doubleByte = b1 + (b2 << 8); 

请注意，我用b1作为低字节，b2为高字节。其余的很简单：分配一个长度为字节数组一半长度的int的数组，然后迭代你的字节数组来构建新的int数组。希望这可以帮助。

Answer 2

也许我理解你的问题完全错误。

public class Main { 
    // run this 
    public static void main(String[] args) {  

     // create the array and split it 
     Main.splitArray(new byte[10]); 
    } 

    // split the array 
    public static void splitArray(byte[] byteArray) { 
     int halfSize = 0; // holds the half of the length of the array 
     int length = byteArray.length; // get the length of the array 
     byte[] b1 = new byte[length/2]; // first half 
     byte[] b2 = new byte[length/2]; // second half 
     int index = 0; 

     if (length % 2 == 0) { // check if the array length is even 
      halfSize = length/2; // get the half length 

      while (index < halfSize) { // copy first half 
       System.out.println("Copy index " + index + " into b1's index " + index); 
       b1[index] = byteArray[index]; 
       index++; 
      } 

      int i = 0; // note the difference between "i" and "index" ! 
      while (index < length) { // copy second half 
       System.out.println("Copy index " + index + " into b2's index " + i);// note the difference between "i" and "index" ! 
       b2[i] = byteArray[index];// note the difference between "i" and "index" ! 
       index++; 
       i++; //dont forget to iterate this, too 
      } 

     } else { 
      System.out.println("Length of array is not even."); 
     } 
    } 
}