2013-04-01 33 views
19

我有一个小型的C#web应用程序。如何获取允许用户通过HTTP POST发送文件的c#代码。它应该能够发送文本文件,图像文件,excel,csv ,doc(所有类型的文件),而不使用流读取器和所有。在c#中使用HTTP POST发送文件

+0

http://stackoverflow.com/questions/566462/upload-files-with-httpwebrequest-multipart-form-data –

+2

'我已经试过各种方法,但没有人帮助我。 ' - 如果你展示了一些你已经尝试过的方法,我们可能会发现他们有什么问题。现在,很难进行建设性的讨论。 –

+1

重复[使用C#通过HTTP POST发送文件](http://stackoverflow.com/questions/1131425/send-a-file-via-http-post-with-c-sharp)和其他各种。显示你曾经尝试过的,以及upvoters,请考虑你是upvoting的问题是一个受欢迎的除了网站或只是一个副本。 – CodeCaster

回答

12

你可以试试下面的代码:

public void PostMultipleFiles(string url, string[] files) 
{ 
    string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x"); 
    HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create(url); 
    httpWebRequest.ContentType = "multipart/form-data; boundary=" + boundary; 
    httpWebRequest.Method = "POST"; 
    httpWebRequest.KeepAlive = true; 
    httpWebRequest.Credentials = System.Net.CredentialCache.DefaultCredentials; 
    Stream memStream = new System.IO.MemoryStream(); 
    byte[] boundarybytes =System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary  +"\r\n"); 
    string formdataTemplate = "\r\n--" + boundary + "\r\nContent-Disposition: form-data; name=\"{0}\";\r\n\r\n{1}"; 
    string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\n Content-Type: application/octet-stream\r\n\r\n"; 
    memStream.Write(boundarybytes, 0, boundarybytes.Length); 
    for (int i = 0; i < files.Length; i++) 
    { 
     string header = string.Format(headerTemplate, "file" + i, files[i]); 
     //string header = string.Format(headerTemplate, "uplTheFile", files[i]); 
     byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header); 
     memStream.Write(headerbytes, 0, headerbytes.Length); 
     FileStream fileStream = new FileStream(files[i], FileMode.Open, 
     FileAccess.Read); 
     byte[] buffer = new byte[1024]; 
     int bytesRead = 0; 
     while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0) 
     { 
      memStream.Write(buffer, 0, bytesRead); 
     } 
     memStream.Write(boundarybytes, 0, boundarybytes.Length); 
     fileStream.Close(); 
    } 
    httpWebRequest.ContentLength = memStream.Length; 
    Stream requestStream = httpWebRequest.GetRequestStream(); 
    memStream.Position = 0; 
    byte[] tempBuffer = new byte[memStream.Length]; 
    memStream.Read(tempBuffer, 0, tempBuffer.Length); 
    memStream.Close(); 
    requestStream.Write(tempBuffer, 0, tempBuffer.Length); 
    requestStream.Close(); 
    try 
    { 
     WebResponse webResponse = httpWebRequest.GetResponse(); 
     Stream stream = webResponse.GetResponseStream(); 
     StreamReader reader = new StreamReader(stream); 
     string var = reader.ReadToEnd(); 

    } 
    catch (Exception ex) 
    { 
     response.InnerHtml = ex.Message; 
    } 
    httpWebRequest = null; 
} 
+14

只是倾销50行代码不是答案。这个问题有很多答案,许多这样的代码已经内置在.NET类型中,比如WebClient和HttpClient。 – CodeCaster

+0

你能解释一下接收者页面的检索过程吗? –

+1

你可以举一个URL的例子.. 它包含文件名吗? –

8

试试这个

string fileToUpload = @"c:\user\test.txt"; 
string url = "http://example.com/upload"; 
using (var client = new WebClient()) 
{ 
byte[] result = client.UploadFile(url, fileToUpload); 
string responseAsString = Encoding.Default.GetString(result); 
} 
9

使用.NET 4.5(或通过添加的NuGet的Microsoft.Net.Http包.NET 4.0)有一个更简单的方法模拟表单请求。这里有一个例子:

private System.IO.Stream Upload(string actionUrl, string paramString, Stream paramFileStream, byte [] paramFileBytes) 
{ 
    HttpContent stringContent = new StringContent(paramString); 
    HttpContent fileStreamContent = new StreamContent(paramFileStream); 
    HttpContent bytesContent = new ByteArrayContent(paramFileBytes); 
    using (var client = new HttpClient()) 
    using (var formData = new MultipartFormDataContent()) 
    { 
     formData.Add(stringContent, "param1", "param1"); 
     formData.Add(fileStreamContent, "file1", "file1"); 
     formData.Add(bytesContent, "file2", "file2"); 
     var response = client.PostAsync(actionUrl, formData).Result; 
     if (!response.IsSuccessStatusCode) 
     { 
      return null; 
     } 
     return response.Content.ReadAsStreamAsync().Result; 
    } 
} 
+0

是否必须始终使用多部分表单数据? – Abhijeet

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