我特林通过AWSCredentials发送邮件,但得到一个异常java.lang.NoClassDefFoundError:组织/阿帕奇/ HTTP /康涅狄格州/方案/ SchemeSocketFactory
java.lang.NoClassDefFoundError: org/apache/http/conn/scheme/SchemeSocketFactory
我已经添加了这些罐子:
- AWS-java的SDK-1.3.11.jar
- AWS-java的SDK-1.3.11-javadoc.jar
- AWS-java的SDK-1.3.11-sources.jar
- aws- Java的SDK流 - 构建 - 工具 - 1.3.11.jar
- 的commons-logging.jar
- 的HttpClient-4.0-alpha4.jar
- 的HttpCore-4.0-alpha6.jar
- 的log4j-1.2。 13.jar
- 的mail.jar
我的Java代码 -
import com.amazonaws.auth.AWSCredentials;
import com.amazonaws.auth.BasicAWSCredentials;
import com.amazonaws.services.simpleemail.AmazonSimpleEmailServiceClient;
import com.amazonaws.services.simpleemail.model.*;
import java.util.LinkedList;
public class SESExample {
public static final String ACCESS_KEY = "My Access";
public static final String SECRET_KEY = "My Secret";
public static void main(String args[]) {
String sender = "[email protected]"; // should be verified email
LinkedList<String> recipients = new LinkedList<String>();
recipients.add("[email protected]"); // again a verified email, if you are in sandbox
SendMail(sender, recipients, "Hi", "Hi how are u?");
}
public static void SendMail(String sender, LinkedList<String> recipients, String subject, String body) {
Destination destination = new Destination(recipients);
Content subjectContent = new Content(subject);
Content bodyContent = new Content(body);
Body msgBody = new Body(bodyContent);
Message msg = new Message(subjectContent, msgBody);
SendEmailRequest request = new SendEmailRequest(sender, destination, msg);
AWSCredentials credentials = new BasicAWSCredentials(ACCESS_KEY, SECRET_KEY);
AmazonSimpleEmailServiceClient sesClient = new AmazonSimpleEmailServiceClient(credentials);
SendEmailResult result = sesClient.sendEmail(request);
System.out.println(result);
}
}
我也试图搜索这个罐子,但没有得到。 我使用错误的jar无法确定。 任何人都可以告诉我是什么问题?
我
你能告诉我们classpath的文件吗?此行中出现 – Zakaria