PHP：SQL值作为文件名

Question

我有这样的代码：

<?php 
    $servername = "Jarvis"; 
    $username = "TonyStark"; 
    $password = "iLoveIronMan"; 
    $dbname = "StarkCompany"; 

    // Create connection 
    $conn = new mysqli($servername, $username, $password, $dbname); 
    // Check connection 
    if ($conn->connect_error) { 
     die("Connection failed: " . $conn->connect_error); 
    } 

    $sql = "SELECT o.order_id, o.customer_id, op.quantity, op.model FROM oc_order o INNER JOIN oc_order_product op ON o.order_id = op.order_id INNER JOIN oc_product p ON op.product_id = p.product_id WHERE o.order_status_id = 2 AND p.location = 1 ORDER BY o.order_id, op.model"; 

    $file = fopen('../files/in/filename.csv', 'w'); 

    if ($rows = mysqli_query($conn, $sql)) 
    { 

     while ($row = mysqli_fetch_assoc($rows)) 
     { 
      fputcsv($file, $row, ';'); 
     } 

     mysqli_free_result($rows); 
    } 

    mysqli_close($conn); 

    fclose($file); 
    ?> 

现在：我如何可以采取例如表o.order_id的SQL值，并使用该值对我的名？文件名应该是example（o.order_id）.csv。这可能吗？

Answer 1

你可以让你的生活被命名值这样简单：

$sql = "SELECT o.order_id as filename, o.customer_id, op.quantity, op.model FROM oc_order o INNER JOIN oc_order_product op ON o.order_id = op.order_id INNER JOIN oc_product p ON op.product_id = p.product_id WHERE o.order_status_id = 2 AND p.location = 1 ORDER BY o.order_id, op.model"; 

那么当你处理行，你可以使用

$rows['filename']