MySQL - 集团由UNION查询

Question

我一直在试图找到一个解决方案，我的问题现在几个小时，不能拿出正确的查询。我有两张表，stocktake_scans和stocktake_items。我需要从两个表中选择数据并将它们组合在一起。我现在的查询是这样的：

SELECT 
a.department_description, a.sub_department_description, a.total_cost, a.total_retail, SUM(a.qty) AS qty, a.total_vat, a.vat_rate 
FROM ( 
    SELECT (CASE WHEN TRIM(IFNULL(sp.department_description, '')) = '' THEN 'N/A' ELSE sp.department_description END) AS department_description, 
    (CASE WHEN TRIM(IFNULL(sp.sub_department_description, '')) = '' THEN 'N/A' ELSE sp.sub_department_description END) AS sub_department_description, 
    SUM(sp.unit_cost_price * ss.quantity) AS total_cost, 
    SUM(sp.unit_retail_price * ss.quantity) AS total_retail, 
    sum(ss.quantity) AS qty, 
    (SUM(sp.unit_cost_price*ss.quantity)) * (sv.vat_rate/100) AS total_vat, 
    sv.vat_rate as vat_rate 
    FROM 
     stocktake_scans ss 
     INNER JOIN stocktake_products sp ON ss.stocktake_product_id = sp.stocktake_product_id 
     LEFT JOIN stocktake_vat_codes sv ON sv.vat_code = sp.vat_code AND sv.stocktake_id = '5778' 
     WHERE ss.stocktake_id = '5778' 
     GROUP BY sp.department_description, sp.sub_department_description 
    UNION ALL 
     SELECT (CASE WHEN TRIM(IFNULL(si.department_description, '')) = '' THEN 'N/A' ELSE si.department_description END) AS department_description, 
     'N/A' as sub_department_description, 
     SUM(si.unit_cost_price * si.quantity) AS total_cost, 
     SUM(si.unit_retail_price * si.quantity) AS total_retail, 
     sum(si.quantity) AS qty, 
     SUM(si.unit_cost_price * quantity)*(sv.vat_rate/100) AS total_vat, 
     sv.vat_rate as vat_rate 
     FROM stocktake_items si 
     LEFT JOIN stocktake_vat_codes sv ON sv.vat_code = si.vat_code AND sv.stocktake_id = '5778' 
     WHERE si.stocktake_id = '5778' GROUP BY si.department_description) a 
    GROUP 
     BY a.department_description, a.sub_department_description 

这并没有完全完成这项工作。我从stocktake_scans获取所有数据，然后从stocktake_items获取数据。

我得到了下面的第一个结果

，然后在Excel文件的最后，我也得到这个

什么是这样做的正确的方式，使这两个酒精数字显示在一个地方？

Answer 1

前的最后GROUP BY